   Chapter 15.5, Problem 3E

Chapter
Section
Textbook Problem

Find the area of the surface.3. The part of the plane 3x + 2y + z = 6 that lies in the first octant

To determine

To find: The area of given surface.

Explanation

Given:

The part of the plane, 3x+2y+z=6 .

The region D lies in the first octant.

Formula used:

The surface area with equation z=f(x,y),(x,y)D , where fx and fy are continuous, is A(S)=D[fx(x,y)]2+[fy(x,y)]2+1dA .

Here, D is the given region.

Calculation:

Express the given equation as follows.

3x+2y+z=6z=63x2y

The partial derivatives fx and fy are,

fx=3</

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