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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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Exercise 15.11 What volume of 0.50 N H2SO4 is required to react exactly with 0.250 L of 0.80 NKOH?

Interpretation Introduction

Interpretation:

The volume of 0.50 N H2SO4 is needed to react with 0.250 L of 0.80 N KOH should be calculated.

Concept Introduction:

Normality of the solution is equal to the ratio of equivalent weight in grams of solute to the volume of solution in litres.

The mathematical expression is given by:

Normality = gram equivalent weight volume of solution in litres

Now, 1 equivalent of acid consist of same number of H+ as the number of OH- ions present in 1 equivalent of base. Equal equivalents of acid and base are required for neutralization. Thus, expression is given by:

NacidVacid=NbaseVbase.

Explanation

Given information:

Normality of H2SO4 = 0.50 N

Normality of KOH = 0.80 N

Volume of KOH = 0.250 L

The relationship which is used to determine the volume of H2SO4 is given by:

NacidVacid=NbaseVbase

Put the values, we get:

0

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Chapter 15 Solutions

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Sect-15.8 P-15.10SCSect-15.8 P-15.11SCCh-15 P-1ALQCh-15 P-2ALQCh-15 P-3ALQCh-15 P-4ALQCh-15 P-5ALQCh-15 P-6ALQCh-15 P-7ALQCh-15 P-8ALQCh-15 P-9ALQCh-15 P-10ALQCh-15 P-11ALQCh-15 P-12ALQCh-15 P-13ALQCh-15 P-14ALQCh-15 P-1QAPCh-15 P-2QAPCh-15 P-3QAPCh-15 P-4QAPCh-15 P-5QAPCh-15 P-6QAPCh-15 P-7QAPCh-15 P-8QAPCh-15 P-9QAPCh-15 P-10QAPCh-15 P-11QAPCh-15 P-12QAPCh-15 P-13QAPCh-15 P-14QAPCh-15 P-15QAPCh-15 P-16QAPCh-15 P-17QAPCh-15 P-18QAPCh-15 P-19QAPCh-15 P-20QAPCh-15 P-21QAPCh-15 P-22QAPCh-15 P-23QAPCh-15 P-24QAPCh-15 P-25QAPCh-15 P-26QAPCh-15 P-27QAPCh-15 P-28QAPCh-15 P-29QAPCh-15 P-30QAPCh-15 P-31QAPCh-15 P-32QAPCh-15 P-33QAPCh-15 P-34QAPCh-15 P-35QAPCh-15 P-36QAPCh-15 P-37QAPCh-15 P-38QAPCh-15 P-39QAPCh-15 P-40QAPCh-15 P-41QAPCh-15 P-42QAPCh-15 P-43QAPCh-15 P-44QAPCh-15 P-45QAPCh-15 P-46QAPCh-15 P-47QAPCh-15 P-48QAPCh-15 P-49QAPCh-15 P-50QAPCh-15 P-51QAPCh-15 P-52QAPCh-15 P-53QAPCh-15 P-54QAPCh-15 P-55QAPCh-15 P-56QAPCh-15 P-57QAPCh-15 P-58QAPCh-15 P-59QAPCh-15 P-60QAPCh-15 P-61QAPCh-15 P-62QAPCh-15 P-63QAPCh-15 P-64QAPCh-15 P-65QAPCh-15 P-66QAPCh-15 P-67QAPCh-15 P-68QAPCh-15 P-69QAPCh-15 P-70QAPCh-15 P-71QAPCh-15 P-72QAPCh-15 P-73QAPCh-15 P-74QAPCh-15 P-75QAPCh-15 P-76QAPCh-15 P-77QAPCh-15 P-78QAPCh-15 P-79QAPCh-15 P-80QAPCh-15 P-81QAPCh-15 P-82QAPCh-15 P-83QAPCh-15 P-84QAPCh-15 P-85QAPCh-15 P-86QAPCh-15 P-87QAPCh-15 P-88QAPCh-15 P-89APCh-15 P-90APCh-15 P-91APCh-15 P-92APCh-15 P-93APCh-15 P-94APCh-15 P-95APCh-15 P-96APCh-15 P-97APCh-15 P-98APCh-15 P-99APCh-15 P-100APCh-15 P-101APCh-15 P-102APCh-15 P-103APCh-15 P-104APCh-15 P-105APCh-15 P-106APCh-15 P-107APCh-15 P-108APCh-15 P-109APCh-15 P-110APCh-15 P-111APCh-15 P-112APCh-15 P-113APCh-15 P-114APCh-15 P-115APCh-15 P-116APCh-15 P-117APCh-15 P-118APCh-15 P-119APCh-15 P-120APCh-15 P-121APCh-15 P-122APCh-15 P-123APCh-15 P-124APCh-15 P-125APCh-15 P-126APCh-15 P-127APCh-15 P-128APCh-15 P-129APCh-15 P-130APCh-15 P-131APCh-15 P-132APCh-15 P-133APCh-15 P-134APCh-15 P-135APCh-15 P-136APCh-15 P-137CPCh-15 P-138CPCh-15 P-139CPCh-15 P-140CPCh-15 P-141CPCh-15 P-142CPCh-15 P-143CPCh-15 P-1CRCh-15 P-2CRCh-15 P-3CRCh-15 P-4CRCh-15 P-5CRCh-15 P-6CRCh-15 P-7CRCh-15 P-8CRCh-15 P-9CRCh-15 P-10CRCh-15 P-11CRCh-15 P-12CRCh-15 P-13CRCh-15 P-14CRCh-15 P-15CRCh-15 P-16CRCh-15 P-17CRCh-15 P-18CRCh-15 P-19CRCh-15 P-20CRCh-15 P-21CRCh-15 P-22CRCh-15 P-23CRCh-15 P-24CRCh-15 P-25CRCh-15 P-26CRCh-15 P-27CRCh-15 P-28CRCh-15 P-29CRCh-15 P-30CRCh-15 P-31CRCh-15 P-32CRCh-15 P-33CRCh-15 P-34CRCh-15 P-35CRCh-15 P-36CRCh-15 P-37CRCh-15 P-38CRCh-15 P-39CRCh-15 P-40CRCh-15 P-41CRCh-15 P-42CR

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