   Chapter 15.8, Problem 15.11SC ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# Exercise 15.11 What volume of 0.50 N H2SO4 is required to react exactly with 0.250 L of 0.80 NKOH?

Interpretation Introduction

Interpretation:

The volume of 0.50 N H2SO4 is needed to react with 0.250 L of 0.80 N KOH should be calculated.

Concept Introduction:

Normality of the solution is equal to the ratio of equivalent weight in grams of solute to the volume of solution in litres.

The mathematical expression is given by:

Normality = gram equivalent weight volume of solution in litres

Now, 1 equivalent of acid consist of same number of H+ as the number of OH- ions present in 1 equivalent of base. Equal equivalents of acid and base are required for neutralization. Thus, expression is given by:

NacidVacid=NbaseVbase.

Explanation

Given information:

Normality of H2SO4 = 0.50 N

Normality of KOH = 0.80 N

Volume of KOH = 0.250 L

The relationship which is used to determine the volume of H2SO4 is given by:

NacidVacid=NbaseVbase

Put the values, we get:

0

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