   Chapter 15.8, Problem 15.8QQ

Chapter
Section
Textbook Problem

Suppose the electric field of Quick Quiz 15.7 is tilted 60° away from the positive z-direction. Calculate the magnitude of the flux through the same area. (a) 0 (b) 10.0 N · m2/C (c) 20.0 N · m2/C (d) More information is needed

To determine
The magnitude of flux.

Explanation

Given info: The electric field has a magnitude of 5.00 N/C and is along z direction. The area of the rectangle is 4.00m2 . The angle between the electric field and area vector is 60ο

The magnitude of flux is given by,

ϕE=EAcosθ (I)

• E is the electric field.
• A is the area vector.
• θ is the angle between E and A.

Conclusion:

Substitute 5.00 N/C for E, 4.00m2 for A and 60ο for θ in Equation (I).

ϕE=(5

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