Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Textbook Question
Chapter 15.SE, Problem 27AP
Look at the five resonance structures for phenanthrene (Problem 15-26), and predict which of its carbon-carbon bonds is shortest.
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Chapter 15 Solutions
Organic Chemistry
Ch. 15.1 - Prob. 1PCh. 15.1 - Give IUPAC names for the following compounds:Ch. 15.1 - Prob. 3PCh. 15.2 - Pyridine is a flat, hexagonal molecule with bond...Ch. 15.3 - Prob. 5PCh. 15.4 - Draw the five resonance structures of the...Ch. 15.4 - Prob. 7PCh. 15.4 - Prob. 8PCh. 15.5 - Prob. 9PCh. 15.5 - Prob. 10P
Ch. 15.6 - Prob. 11PCh. 15.6 - How many electrons does each of the four nitrogen...Ch. 15.SE - Give IUPAC names for the following substances (red...Ch. 15.SE - All-cis cyclodecapentaene is a stable molecule...Ch. 15.SE - 1, 6-Methanonaphthalene has an interesting 1H NMR...Ch. 15.SE - Prob. 16VCCh. 15.SE - Azulene, an isomer of naphthalene, has a...Ch. 15.SE - Give IUPAC names for the following compounds:Ch. 15.SE - Draw structures corresponding to the following...Ch. 15.SE - Prob. 20APCh. 15.SE - Prob. 21APCh. 15.SE - Draw and name all possible aromatic compounds with...Ch. 15.SE - Propose structures for aromatic hydrocarbons that...Ch. 15.SE - Look at the three resonance structures of...Ch. 15.SE - Prob. 25APCh. 15.SE - Prob. 26APCh. 15.SE - Look at the five resonance structures for...Ch. 15.SE - Prob. 28APCh. 15.SE - 3-Chlorocyclopropene, on treatment with AgBF4,...Ch. 15.SE - Prob. 30APCh. 15.SE - Prob. 31APCh. 15.SE - Prob. 32APCh. 15.SE - Which would you expect to be most stable,...Ch. 15.SE - How might you convert 1, 3, 5, 7-cyclononatetraene...Ch. 15.SE - Calicene, like azulene (Problem 15-17), has an...Ch. 15.SE - Pentalene is a most elusive molecule that has been...Ch. 15.SE - Prob. 37APCh. 15.SE - Prob. 38APCh. 15.SE - Compound A, C8H10, yields three substitution...Ch. 15.SE - Prob. 40APCh. 15.SE - Propose structures for compounds that fit the...Ch. 15.SE - Prob. 42APCh. 15.SE - Prob. 43APCh. 15.SE - N-Phenylsydnone, so-named because it was first...Ch. 15.SE - Prob. 45APCh. 15.SE - Prob. 46APCh. 15.SE - Prob. 47APCh. 15.SE - Propose a structure for a molecule C14H12 that has...Ch. 15.SE - The proton NMR spectrum for a compound with...Ch. 15.SE - The proton NMR spectrum of a compound with formula...Ch. 15.SE - Aromatic substitution reactions occur by addition...Ch. 15.SE - Prob. 52APCh. 15.SE - Consider the aromatic anions below and their...Ch. 15.SE - After the reaction below, the chemical shift of Ha...Ch. 15.SE - Prob. 55APCh. 15.SE - Azo dyes are the major source of artificial color...
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- N-Phenylsydnone, so-named because it was first studied at the University of Sydney, Australia, behaves like a typical aromatic molecule. Explain, using the HĂ¼ckel 4n + 2 rule.arrow_forward16-17 Propylamine (bp 48°C), ethylmethylamine (bp 37°C), and trimethylamine (bp 3°C) are constitutional isomers with the molecular formula C3HgN. Account for the fact that trimethylamine has the lowest boiling point of the three and propylamine has the highest.arrow_forwardRank the following acids in decreasing acidity. Explain your answer CH2ClCOOH, CHCl2COOH, CH3COOHarrow_forward
- 1, 6-Methanonaphthalene has an interesting 1H NMR spectrum in which the eight hydrogens around the perimeter absorb at 6.9 to 7.3 δ, while the two CH2 protons absorb at -0.5 δ. Tell whether it is aromatic, and explain its NMR spectrum.arrow_forwardBENZOIC ACID(Screenshot2113) : Find Bonds, Absoprtion Peaks [cm-1] and their functional groups (Alkane/Alyne/Alchol/Arene/etc..)arrow_forwardElectrophilic aromatic substitution usually occurs at the 1-position of naphthalene, also called the a position. Predict the major products of the reactions of naphthalene with HNO3, H2SO4.arrow_forward
- Thiocyanic acid (HSCN) is an inorganic acid (pKa = 1.1 at 25 °C) that can be classified as “strong” largely due to resonance stabilization of its conjugate base, thiocyanate (SCN– ). In the space provided below, draw Lewis electron dot structures of SCN- and all of its important resonance forms.arrow_forwardHow do you explain why phenol is the o-p driver, while nitro benzene is m-directional? Explain by showing the resonance structures.arrow_forwardTreatment of (CH3)2CHCH(OH)CH2CH3 with TsOH affords two products(M and N) with molecular formula C6H12. The 1H NMR spectra of M and Nare given below. Propose structures for M and N, and draw a mechanismto explain their formation.arrow_forward
- How would you explain the o-p directing formation of phenol, while nitro benzene is m-directional? Explain by showing the resonance structures.arrow_forward13a. Compound C9H10O a=7.43 ppm, multiplet 5H B=3.66 ppm singlet 2H C= 2.05 ppm singlet 3H Draw the structure and indicate all proton resonancesarrow_forwardBenzoic acid, Ph-COOH (C6H5CO2H), is not soluble in water while it dissolves in ether (diethyl ether), (CH3CH2)2O. Yet upon treatment with sodium hydroxide, benzoic acid turns hydrophilic and dissolves in water. Provide chemical explanation of this observation.arrow_forward
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