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Science
ChemistryChemistry & Chemical Reactivity10th Edition

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Chapter 16, Problem 104GQ
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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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Problem 6PS
Problem 7PS
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Problem 82PS
Problem 83PS
Problem 84PS
Problem 85GQ
Problem 86GQ
Problem 87GQ
Problem 88GQ
Problem 89GQ
Problem 90GQ
Problem 91GQ
Problem 92GQ
Problem 93GQ
Problem 94GQ
Problem 95GQ
Problem 96GQ
Problem 97GQ
Problem 98GQ
Problem 99GQ
Problem 100GQ
Problem 101GQ
Problem 102GQ
Problem 103GQ
Problem 104GQ
Problem 105GQ
Problem 106GQ
Problem 107GQ
Problem 108GQ
Problem 109GQ
Problem 110GQ
Problem 111IL
Problem 112IL
Problem 113IL
Problem 114IL
Problem 115IL
Problem 116IL
Problem 117IL
Problem 118IL
Problem 119SCQ
Problem 120SCQ
Problem 121SCQ
Problem 122SCQ
Problem 123SCQ
Problem 124SCQ
Problem 125SCQ
Problem 126SCQ
Problem 127SCQ
Problem 128SCQ
Problem 129SCQ
BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The equilibrium constant for the reaction of hydrochloric acid and ammonia is 1.8 × 109 (page 726). Confirm this value.

Interpretation Introduction

Interpretation:

The equilibrium constant of the reaction is 1.8×109 has to be proved.

Concept introduction:

Equilibrium constants:

The equilibrium constant is used to quantitative measurement of the strength of the acid and bases in the water.

Ka is an acid constant for equilibrium reactions.

HA + H2O⇌H3O++ A-Ka= [H3O+][A-][HA]

Kb is a base constant for equilibrium reaction.

BOH + H2O⇌B++ OH-Ka= [B+][OH-][BOH]

Explanation

Hydrochloric acid reacts with water to form H3O+. It reacts with NH3 to form NH4+. The conjugate acid of NH3 and H2O.

Let’s write the equilibrium chemical reaction between NH3 and H3O+

H3O+(aq)+NH3(aq)⇌NH4+(aq)+H2O(l)

Equilibrium expression:

K= [NH4+][NH3][H3O+]= 1.8×109                             (1)

H2O(l)⇌H3O+(aq)+OH-(aq)Kw= [H3O+][OH-] = 1×10-14                     �

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Sect-16.2 P-16.1CYUSect-16.4 P-16.2CYUSect-16.5 P-16.3CYUSect-16.7 P-16.4CYUSect-16.7 P-16.5CYUSect-16.7 P-16.6CYUSect-16.7 P-16.7CYUSect-16.7 P-16.8CYUSect-16.8 P-16.9CYUSect-16.10 P-1.1ACP
Sect-16.10 P-1.2ACPSect-16.10 P-1.3ACPSect-16.10 P-2.1ACPSect-16.10 P-2.2ACPSect-16.10 P-2.3ACPSect-16.10 P-2.4ACPSect-16.10 P-2.5ACPCh-16 P-1PSCh-16 P-2PSCh-16 P-3PSCh-16 P-4PSCh-16 P-5PSCh-16 P-6PSCh-16 P-7PSCh-16 P-8PSCh-16 P-9PSCh-16 P-10PSCh-16 P-11PSCh-16 P-12PSCh-16 P-13PSCh-16 P-14PSCh-16 P-15PSCh-16 P-16PSCh-16 P-17PSCh-16 P-18PSCh-16 P-19PSCh-16 P-20PSCh-16 P-21PSCh-16 P-22PSCh-16 P-23PSCh-16 P-24PSCh-16 P-25PSCh-16 P-26PSCh-16 P-27PSCh-16 P-28PSCh-16 P-29PSCh-16 P-30PSCh-16 P-31PSCh-16 P-32PSCh-16 P-33PSCh-16 P-34PSCh-16 P-35PSCh-16 P-36PSCh-16 P-37PSCh-16 P-38PSCh-16 P-39PSCh-16 P-40PSCh-16 P-41PSCh-16 P-42PSCh-16 P-43PSCh-16 P-44PSCh-16 P-45PSCh-16 P-46PSCh-16 P-47PSCh-16 P-48PSCh-16 P-49PSCh-16 P-50PSCh-16 P-51PSCh-16 P-52PSCh-16 P-53PSCh-16 P-54PSCh-16 P-55PSCh-16 P-56PSCh-16 P-57PSCh-16 P-58PSCh-16 P-59PSCh-16 P-60PSCh-16 P-61PSCh-16 P-62PSCh-16 P-63PSCh-16 P-64PSCh-16 P-65PSCh-16 P-66PSCh-16 P-67PSCh-16 P-68PSCh-16 P-69PSCh-16 P-70PSCh-16 P-71PSCh-16 P-72PSCh-16 P-73PSCh-16 P-74PSCh-16 P-75PSCh-16 P-76PSCh-16 P-77PSCh-16 P-78PSCh-16 P-79PSCh-16 P-80PSCh-16 P-81PSCh-16 P-82PSCh-16 P-83PSCh-16 P-84PSCh-16 P-85GQCh-16 P-86GQCh-16 P-87GQCh-16 P-88GQCh-16 P-89GQCh-16 P-90GQCh-16 P-91GQCh-16 P-92GQCh-16 P-93GQCh-16 P-94GQCh-16 P-95GQCh-16 P-96GQCh-16 P-97GQCh-16 P-98GQCh-16 P-99GQCh-16 P-100GQCh-16 P-101GQCh-16 P-102GQCh-16 P-103GQCh-16 P-104GQCh-16 P-105GQCh-16 P-106GQCh-16 P-107GQCh-16 P-108GQCh-16 P-109GQCh-16 P-110GQCh-16 P-111ILCh-16 P-112ILCh-16 P-113ILCh-16 P-114ILCh-16 P-115ILCh-16 P-116ILCh-16 P-117ILCh-16 P-118ILCh-16 P-119SCQCh-16 P-120SCQCh-16 P-121SCQCh-16 P-122SCQCh-16 P-123SCQCh-16 P-124SCQCh-16 P-125SCQCh-16 P-126SCQCh-16 P-127SCQCh-16 P-128SCQCh-16 P-129SCQ

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