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ChemistryIntroductory Chemistry: A Foundation9th Edition

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Chapter 16, Problem 108CP
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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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Problem 106CP
Problem 107CP
Problem 108CP
BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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. Consider 0.25 M solutions of the following salts: NaCl. RbOC1, KI, Ba(ClO4),, and NH4NO3. For each salt, indicate whether the solution is acidic, basic, or neutral.

Interpretation Introduction

Interpretation:

Considering 0.25 M solutions of the salts: NaCl, RbOCl, KI, Ba(ClO4 )2 and NH4 NO3, whether the solution is acidic, basic or neutral should be indicated.

Concept Introduction:

When a salt is dissolved in water, it reacts with water to produce H3 O+ and OH-. This is called Hydrolysis reaction. Based on the strength of ion acts as acid or base, the pH of the solution varies. A salt can be made either by reacting strong acid, strong base or weak acid, strong base or strong acid, weak base or weak acid, weak base.

Salts that are made from strong acid strong base do not undergo hydrolysis. So the pH will remain neutral at 7. Salts that are from weak acids and strong base undergo hydrolysis and give a pH greater than 7 which is basic. Salts from strong acids and weak bases undergo hydrolysis and give a pH less than 7 which is acidic. Salts from weak acids and weak bases also undergo hydrolysis, but in order to find the pH of the solution we have to consider the dissociation constants of the acid and the base. Whichever the stronger will determine whether it is acidic or basic.

Explanation

NaCl is made from the strong base NaOH and strong acid HCl. So the NaCl solution is neutral. Na+ does not alter the H+ concentration and Cl- does not attract H+ from water.

RbOCl is made from the strong base RbOH and weak acid HOCl. So the RbOCl solution is basic. The anion in the salt OCl- will accept proton from the water leaving OH-.

KI is made from the strong base KOH and strong acid HI. So the KI solution is neutral. K+ does not alter H+ concentration and I- does not attract protons from the water.

Ba(ClO4 )2 is made from strong base Ba(OH)2 and strong acid HClO4...

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Sect-16.1 P-16.1SCSect-16.2 P-1CTSect-16.3 P-16.2SCSect-16.4 P-16.3SCSect-16.4 P-1CTSect-16.4 P-16.4SCSect-16.4 P-16.5SCSect-16.4 P-16.6SCSect-16.5 P-16.7SCCh-16 P-1ALQ
Ch-16 P-2ALQCh-16 P-3ALQCh-16 P-4ALQCh-16 P-5ALQCh-16 P-6ALQCh-16 P-7ALQCh-16 P-8ALQCh-16 P-9ALQCh-16 P-10ALQCh-16 P-11ALQCh-16 P-12ALQCh-16 P-13ALQCh-16 P-14ALQCh-16 P-15ALQCh-16 P-16ALQCh-16 P-17ALQCh-16 P-1QAPCh-16 P-2QAPCh-16 P-3QAPCh-16 P-4QAPCh-16 P-5QAPCh-16 P-6QAPCh-16 P-7QAPCh-16 P-8QAPCh-16 P-9QAPCh-16 P-10QAPCh-16 P-11QAPCh-16 P-12QAPCh-16 P-13QAPCh-16 P-14QAPCh-16 P-15QAPCh-16 P-16QAPCh-16 P-17QAPCh-16 P-18QAPCh-16 P-19QAPCh-16 P-20QAPCh-16 P-21QAPCh-16 P-22QAPCh-16 P-23QAPCh-16 P-24QAPCh-16 P-25QAPCh-16 P-26QAPCh-16 P-27QAPCh-16 P-28QAPCh-16 P-29QAPCh-16 P-30QAPCh-16 P-31QAPCh-16 P-32QAPCh-16 P-33QAPCh-16 P-34QAPCh-16 P-35QAPCh-16 P-36QAPCh-16 P-37QAPCh-16 P-38QAPCh-16 P-39QAPCh-16 P-40QAPCh-16 P-41QAPCh-16 P-42QAPCh-16 P-43QAPCh-16 P-44QAPCh-16 P-45QAPCh-16 P-46QAPCh-16 P-47QAPCh-16 P-48QAPCh-16 P-49QAPCh-16 P-50QAPCh-16 P-51QAPCh-16 P-52QAPCh-16 P-53QAPCh-16 P-54QAPCh-16 P-55QAPCh-16 P-56QAPCh-16 P-57QAPCh-16 P-58QAPCh-16 P-59QAPCh-16 P-60QAPCh-16 P-61QAPCh-16 P-62QAPCh-16 P-63QAPCh-16 P-64QAPCh-16 P-65APCh-16 P-66APCh-16 P-67APCh-16 P-68APCh-16 P-69APCh-16 P-70APCh-16 P-71APCh-16 P-72APCh-16 P-73APCh-16 P-74APCh-16 P-75APCh-16 P-76APCh-16 P-77APCh-16 P-78APCh-16 P-79APCh-16 P-80APCh-16 P-81APCh-16 P-82APCh-16 P-83APCh-16 P-84APCh-16 P-85APCh-16 P-86APCh-16 P-87APCh-16 P-88APCh-16 P-89APCh-16 P-90APCh-16 P-91APCh-16 P-92APCh-16 P-93APCh-16 P-94APCh-16 P-95APCh-16 P-96APCh-16 P-97APCh-16 P-98APCh-16 P-99APCh-16 P-100APCh-16 P-101APCh-16 P-102APCh-16 P-103APCh-16 P-104APCh-16 P-105APCh-16 P-106CPCh-16 P-107CPCh-16 P-108CP

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