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Consider the system A ( g ) → B ( g ) at25°C. a. Assuming that G A o = 8996 J/mol and G B o = 11 , 718 J/mol , calculate the value of the equilibrium constant for this reaction. b. Calculate the equilibrium pressures that result if 1.00 mole of A( g ) at 1.00 atm and 1.00 mole of B( g ) at 1.00 atm are mixed at 25°C. c. Show by calculations that ∆G = 0 at equilibrium.

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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Section
BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 111CP
Textbook Problem
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Consider the system

A ( g ) B ( g )

at25°C.

a. Assuming that G A o = 8996 J/mol and G B o = 11 , 718 J/mol , calculate the value of the equilibrium constant for this reaction.

b. Calculate the equilibrium pressures that result if 1.00 mole of A(g) at 1.00 atm and 1.00 mole of B(g) at 1.00 atm are mixed at 25°C.

c. Show by calculations that ∆G = 0 at equilibrium.

(a)

Interpretation Introduction

Interpretation: The representation of a system at 25°C is given. The answers are to be calculated for the given options.

Concept introduction: Equilibrium constant, K , is the measure of concentration of reactants and products of a system at equilibrium.

The expression for free energy change is,

ΔG°=RTln(K)

To determine: The value of the equilibrium constant for the given reaction.

Explanation of Solution

Given

Temperature is 25°C .

The value of ΔGA° is 8996J/mol .

The value of ΔGB° is 11,718J/mol .

The stated reaction is,

A(g)B(g)

Formula

The standard free energy change of stated reaction is calculated as,

ΔG°=ΔGB°ΔGA°

Where,

  • ΔG° is the change in free energy of the given reaction.
  • ΔGB° is the change in free energy of product.
  • ΔGA° is the change in free energy of reactant.

Substitute the value of ΔGB° and ΔGA° in the above equation.

ΔG°=ΔGB°ΔGA°=11,718J/mol8996J/mol=2772J/mol_

Given

Temperature is 25°C .

The change in free energy of the given reaction is 2772J/mol

 (b)

Interpretation Introduction

Interpretation: The representation of a system at 25°C is given. The answers are to be calculated for the given options.

Concept introduction: Equilibrium constant, K , is the measure of concentration of reactants and products of a system at equilibrium.

The expression for free energy change is,

ΔG°=RTln(K)

To determine: The value of the equilibrium pressure for the given reaction

(c)

Interpretation Introduction

Interpretation: The representation of a system at 25°C is given. The answers are to be calculated for the given options.

Concept introduction: Equilibrium constant, K , is the measure of concentration of reactants and products of a system at equilibrium.

The expression for free energy change is,

ΔG°=RTln(K)

To show: The value of ΔG=0 at equilibrium by calculations.

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Chapter 16 Solutions

Chemistry: An Atoms First Approach
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