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Impure nickel, refined by smelting sulfide ores in a blast furnace, can be converted into metal from 99.90% to 99.99% purity by the Mond process. The primary reaction involved in the Mond process is Ni ( s ) + 4CO ( g ) ⇌ Ni ( CO ) 4 ( g ) a. Without referring to Appendix 4, predict the sign of ∆S° for the above reaction. Explain. b. The spontaneity of the above reaction is temperature-dependent. Predict the sign of ∆S surr , for this reaction. Explain c . For Ni(CO) 4 ( g ), Δ H f o = − 607 KJ/mol and S ° = 417 J/K ·mol at 298 K. Using these values and data in Appendix 4, calculate ∆H° and ∆S° for the above reaction. d. Calculate the temperature at which ∆ G ° = 0 (K = 1) for the above reaction, assuming that ∆H° and ∆S° do not depend on temperature. e. The first step of the Mood process involves equilibrating impure nickel with CO( g ) and Ni(CO) 4 ( g ) at about 50°C. The purpose of this step is to convert as much nickel as possible into the gas phase. Calculate the equilibrium constant for the above reaction at 50.°C. f. In the second step of the Mood process, the gaseous Ni(CO) 4 is isolated and heated to 227°C. The purpose of this step is to deposit as much nickel as possible as pure solid (the reverse of the preceding reaction). Calculate the equilibrium constant for the preceding reaction at 227°C. g. Why is temperature increased for the second step of the Mood process? h. The Mond process relies on the volatility of Ni(CO) 4 for its success. Only pressures and temperatures at which Ni(CO) 4 is a gas are useful. A recently developed variation of the Mood process carries out the first step at higher pressures and a temperature of l52°C. Estimate the maximum pressure of Ni(CO) 4 (g) that can be attained before the gas will liquefy at 152°C. The boiling point for Ni(CO) 4 is 42°C and the enthalpy of vaporization is 29.0 kJ/mol. [Hint: The phase change reaction and the corresponding equilibrium expression are Ni ( CO ) 4 ( l ) ⇌ Ni ( CO ) 4 ( g ) K = P Ni ( CO ) 4 Ni(CO) 4 ( g ) will liquefy when the pressure of Ni(CO) 4 is greater than the K value.]

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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Chapter
Section
BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 122MP
Textbook Problem
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Impure nickel, refined by smelting sulfide ores in a blast furnace, can be converted into metal from 99.90% to 99.99% purity by the Mond process. The primary reaction involved in the Mond process is

Ni ( s ) + 4CO ( g ) Ni ( CO ) 4 ( g )

a. Without referring to Appendix 4, predict the sign of ∆S° for the above reaction. Explain.

b. The spontaneity of the above reaction is temperature-dependent. Predict the sign of ∆Ssurr, for this reaction. Explain

c. For Ni(CO)4(g), Δ H f o = 607 KJ/mol and S° = 417 J/K ·mol at 298 K. Using these values and data in Appendix 4, calculate ∆H° and ∆S° for the above reaction.

d. Calculate the temperature at which ∆G° = 0 (K = 1) for the above reaction, assuming that ∆H° and ∆S° do not depend on temperature.

e. The first step of the Mood process involves equilibrating impure nickel with CO(g) and Ni(CO)4(g) at about 50°C. The purpose of this step is to convert as much nickel as possible into the gas phase. Calculate the equilibrium constant for the above reaction at 50.°C.

f. In the second step of the Mood process, the gaseous Ni(CO)4 is isolated and heated to 227°C. The purpose of this step is to deposit as much nickel as possible as pure solid (the reverse of the preceding reaction). Calculate the equilibrium constant for the preceding reaction at 227°C.

g. Why is temperature increased for the second step of the Mood process?

h. The Mond process relies on the volatility of Ni(CO)4 for its success. Only pressures and temperatures at which Ni(CO)4 is a gas are useful. A recently developed variation of the Mood process carries out the first step at higher pressures and a temperature of l52°C. Estimate the maximum pressure of Ni(CO)4(g) that can be attained before the gas will liquefy at 152°C. The boiling point for Ni(CO)4 is 42°C and the enthalpy of vaporization is 29.0 kJ/mol.

[Hint: The phase change reaction and the corresponding equilibrium expression are

Ni ( CO ) 4 ( l ) Ni ( CO ) 4 ( g ) K = P Ni ( CO ) 4

Ni(CO)4(g) will liquefy when the pressure of Ni(CO)4 is greater than the K value.]

 (a)

Interpretation Introduction

Interpretation: The given questions based upon Mond process are to be answered.

Concept introduction: The Mond process relies on the volatility of Ni(CO)4 for its success. The temperatures and pressures at which Ni(CO)4 is gas are useful.

To determine: The sign of ΔSο for the reaction.

Explanation of Solution

The given reaction is,

Ni(s)+4CO(g)Ni(Co)4(

(b)

Interpretation Introduction

Interpretation: The given questions based upon Mond process are to be answered.

Concept introduction: The Mond process relies on the volatility of Ni(CO)4 for its success. The temperatures and pressures at which Ni(CO)4 is gas are useful.

To determine: The sign of ΔSsurr for the reaction.

(c)

Interpretation Introduction

Interpretation: The given questions based upon Mond process are to be answered.

Concept introduction: The Mond process relies on the volatility of Ni(CO)4 for its success. The temperatures and pressures at which Ni(CO)4 is gas are useful.

To determine: The value of ΔHο and ΔSο for the reaction.

(d)

Interpretation Introduction

Interpretation: The given questions based upon Mond process are to be answered.

Concept introduction: The Mond process relies on the volatility of Ni(CO)4 for its success. The temperatures and pressures at which Ni(CO)4 is gas are useful.

To determine: The temperature at which ΔGο for the reaction is zero.

(e)

Interpretation Introduction

Interpretation: The given questions based upon Mond process are to be answered.

Concept introduction: The Mond process relies on the volatility of Ni(CO)4 for its success. The temperatures and pressures at which Ni(CO)4 is gas are useful.

To determine: The equilibrium constant for the reaction at 50οC .

(f)

Interpretation Introduction

Interpretation: The given questions based upon Mond process are to be answered.

Concept introduction: The Mond process relies on the volatility of Ni(CO)4 for its success. The temperatures and pressures at which Ni(CO)4 is gas are useful.

To determine: The equilibrium constant for the reaction at 227οC .

(g)

Interpretation Introduction

Interpretation: The given questions based upon Mond process are to be answered.

Concept introduction: The Mond process relies on the volatility of Ni(CO)4 for its success. The temperatures and pressures at which Ni(CO)4 is gas are useful.

To determine: The reason for increase in temperature in second step.

(h)

Interpretation Introduction

Interpretation: The given questions based upon Mond process are to be answered.

Concept introduction: The Mond process relies on the volatility of Ni(CO)4 for its success. The temperatures and pressures at which Ni(CO)4 is gas are useful.

To determine: The maximum pressure of NiCO4(g) that can be attained before the gas liquefy at 152οC .

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Chapter 16 Solutions

Chemistry: An Atoms First Approach
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Ch. 16 - For the process A(l) A(g), which direction is...Ch. 16 - For a liquid, which would you expect to be larger,...Ch. 16 - Gas A2 reacts with gas B2 to form gas AB at a...Ch. 16 - What types of experiments can be carried out to...Ch. 16 - A friend tells you, Free energy G and pressure P...Ch. 16 - You remember that G is related to RT ln(K) but...Ch. 16 - Predict the sign of S for each of the following...Ch. 16 - Is Ssurr favorable or unfavorable for exothermic...Ch. 16 - At 1 atm, liquid water is heated above 100C. 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