Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
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Chapter 16, Problem 16.50E
Interpretation Introduction
Interpretation:
The spin combinations that result from three adjacent hydrogen atoms to create
Concept introduction:
Spectroscopy method is used to identify the structure of the molecule. It is based on the interactions between matter and
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If a sample is placed in a magnetic field of applied field strength = 1.1 Tesla, the spin-up and spin-down 1H nuclei show an energy difference that corresponds to a photon with frequency = 60 MHz. If this same sample is moved into the vicinity of a magnetic field of strength = 5.5 Tesla, what will be the frequency of a photon that could match the energy difference of the spin-up and spin-down states?
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The rotation motion of HCl molecules can be analyzed by treating each molecule as a rigid rotational constant B= 2.07x10^-22 Joules. a) what frequency of radiation will excite the transition from the J=1 energy level to the J=2 level in this case? b) what is the relative probability of observing an HCl molecule at the J=2 energy level, as compared to teh J=1 level, at 25.00 degrees C?
which of the following is a reason electronic spectra of molecules typically contain broad peaks? a. all transtions are allowed, b. excited states have finite lifetimes, c. the molecules are stationary, d. all transitions are forbidden
Chapter 16 Solutions
Physical Chemistry
Ch. 16 - Prob. 16.1ECh. 16 - Prob. 16.2ECh. 16 - Prob. 16.3ECh. 16 - Prob. 16.4ECh. 16 - Prob. 16.5ECh. 16 - Prob. 16.6ECh. 16 - Prob. 16.7ECh. 16 - Prob. 16.8ECh. 16 - Prob. 16.9ECh. 16 - Prob. 16.10E
Ch. 16 - Prob. 16.11ECh. 16 - Prob. 16.12ECh. 16 - Prob. 16.13ECh. 16 - Prob. 16.14ECh. 16 - Prob. 16.15ECh. 16 - Prob. 16.16ECh. 16 - Prob. 16.17ECh. 16 - Prob. 16.18ECh. 16 - Prob. 16.19ECh. 16 - Prob. 16.20ECh. 16 - Prob. 16.21ECh. 16 - Prob. 16.22ECh. 16 - Prob. 16.23ECh. 16 - Prob. 16.24ECh. 16 - Prob. 16.25ECh. 16 - Prob. 16.26ECh. 16 - Prob. 16.27ECh. 16 - Prob. 16.28ECh. 16 - Prob. 16.29ECh. 16 - Prob. 16.30ECh. 16 - Prob. 16.31ECh. 16 - Prob. 16.32ECh. 16 - Prob. 16.33ECh. 16 - Prob. 16.34ECh. 16 - Prob. 16.35ECh. 16 - Prob. 16.36ECh. 16 - Prob. 16.37ECh. 16 - Prob. 16.38ECh. 16 - Prob. 16.39ECh. 16 - Prob. 16.40ECh. 16 - Prob. 16.41ECh. 16 - Prob. 16.42ECh. 16 - Prob. 16.43ECh. 16 - Prob. 16.44ECh. 16 - Prob. 16.45ECh. 16 - a The structure of 2 chloroethanol is usually...Ch. 16 - Prob. 16.47ECh. 16 - Prob. 16.48ECh. 16 - Prob. 16.49ECh. 16 - Prob. 16.50ECh. 16 - Prob. 16.51ECh. 16 - Prob. 16.52ECh. 16 - Prob. 16.53ECh. 16 - Prob. 16.54ECh. 16 - Prob. 16.55ECh. 16 - Prob. 16.56ECh. 16 - A microwave oven emits radiation having a...
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- The spectra that you observe are for approximately 1 x 1012 atoms. So it is likely, that with electronic excitation, many of the electronic energy levels will be readily populated. However, the higher energy levels will be less populated, so what does say about the intensity of the higher energy peaks? Is that observation consistent with the spectrum we measured with the spectrometer?arrow_forwardWhich of the following transitions would require the absorption of the longest wavelength photon? n = 3 --> n = 1 n = 1 --> n = 3 n = 7 --> n = 3 n = 3 --> n = 7arrow_forwardDoes the absorption spectrum of the diatomic molecule HCl depend on the isotope of chlorine contained in the molecule? Explain your reasoning.arrow_forward
- Explain the concept of Nuclear magnetic resonance spectroscopy ?arrow_forwardWhich transition will correspond to the absorption of the greatest amount of energy in a hydrogen atom?arrow_forwardWhich is TRUE for spectroscopy of a mixture? A. The absorbance for a mixture at a particular wavelength is the sum of the absorbances for the components that absorb at the particular wavelength. B. Spectrophotometers can differentiate between mixture components that absorb at the same wavelength. C. Each component in a mixture has the same molar absorptivity at the same wavelength. D. The concentration for each component in a mixture is easily calculated by least squares for guesses of each component when the individual spectra are well resolved.arrow_forward
- Which of the following electronic transitions is allowed and thus expected to have a short lifetime? 3S --> 1P 3S --> 3D 3S --> 3P 3S --> 1Farrow_forwardWhich of the following statements is FALSE? a.) The absorptions in IR are attributed to transitions between rotational energy levels of the molecules. b.) The UV spectrum provides information about the valence electrons. c.) UV absorptions are attributed to electronic transitions. d.) NMR spectrometers use radio frequency energyarrow_forwardWhat are the basic principles on which Atomic Fluorescence Spectroscopy is based?arrow_forward
- Which of these transitions do you expect to release the lowest energy photon? I II IIIarrow_forwardThe lines of the rotational spectrum of HBr are 5.10 x 10^11 Hz apart in frequency. Find the internuclear distance in HBr. (Notes: Since the Br atom is about 80 times more massive than the proton, the reduced mass of an HBr molecule can be taken as just the 1H mass.)arrow_forwardIn the following identify which spectral transitions are allowed and/or forbidden. Give a reason why a transition is forbidden. a.) H(2s^2S_1/2)----> H(2p^2 P_1/2) b.) H(1s^2 S_1/2)----> H(3d^2 D_3/2) c.) H(1s 2S_1/2) ----> H(3p ^2 P_3/2) d.) He(1s^1 S_0)----> He(2p^3 P_1) e.) Ar(3p^1 S_0)----> Ar(4s^1 P_0) f.) Ar(3p^1 S_0)----> Ar(4p^1 P_0) g.) Na(3s^2 S_1/2)---->Na(3p^2 P_1/2)arrow_forward
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