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The wave function for a traveling wave on a taut string is (in SI units) y (x, t) = 0.350 sin (10πt - 3π x + (a) What are the speed and direction of travel of the wave? (b) What is the vertical position of an element of the string at t = 0, x = 0.100 111? What are (c) the wavelength and (d) the frequency of the wave? (e) What is the maximum transverse speed of an element of the string?

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Physics for Scientists and Enginee...

9th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305116399

Solutions

Chapter
Section
BuyFindarrow_forward

Physics for Scientists and Enginee...

9th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305116399
Chapter 16, Problem 16.9P
Textbook Problem
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The wave function for a traveling wave on a taut string is (in SI units)

y(x, t) = 0.350 sin (10πt - 3πx +Chapter 16, Problem 16.9P, The wave function for a traveling wave on a taut string is (in SI units) y(x, t) = 0.350 sin (10t -

(a) What are the speed and direction of travel of the wave? (b) What is the vertical position of an element of the string at t = 0, x = 0.100 111? What are (c) the wavelength and (d) the frequency of the wave? (e) What is the maximum transverse speed of an element of the string?

(a)

To determine

The speed and direction of wave.

Explanation of Solution

Given info: The wave function of the wave is y(x,t)=0.350sin(10πt3πx+π4) .

The unit vector in x direction is i^ and the wave is travelling in x direction.

The standard equation of the wave is,

y(x,t)=Asin(kxωt)

Here,

A is amplitude of the wave.

k is angular wave number of wave.

ω is angular velocity of wave.

t is time period of wave.

The given equation of wave is,

y(x,t)=0.350sin(10πt3πx+π4) (1)

Compare the above two equations

(b)

To determine

The vertical position of the element of string.

(c)

To determine

The wave length of the wave.

(d)

To determine

The frequency of the wave.

(e)

To determine

The maximum transverse speed of the element of string.

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Chapter 16 Solutions

Physics for Scientists and Engineers, Technology Update (No access codes included)
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