Concept explainers
The relationship between Hooke’s law and
Answer to Problem 1ASA
The relationship between Hooke’s law and Simple Harmonic Motion is that any particle that obeying Hooke’s law would execute simple harmonic motion
Explanation of Solution
Hooke’s law:
One of the properties of elasticity that takes twice as much force to stretch out a spring twice as far. This linear dependence of the displacement on force of stretching is known as Hooke’s law.
Hooke’s law states that the force required to the stretch of the spring is directly proportional to stretch.
Write the expression for the Hooke’s law.
Here,
Simple Harmonic Motion:
The motion of a mass on a spring when it is elastic force of restoring given by the Hooke’s law.
The motion of the particle that subjected to restoring force that vibrate to and fro movement from the point of equilibrium is known as Simple Harmonic Motion.
Conclusion:
The relationship between Hooke’s law and Simple Harmonic Motion is that any particle that obeying Hooke’s law would execute simple harmonic motion
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Chapter 16 Solutions
Physics Laboratory Experiments
- What is simple harmonic oscillation? Express your answer verbally,mathematically, and visually.arrow_forwardDescribe how the two bars (KE and PE) are related to each other and how these relationships change as the pendulum moves through its cycle.arrow_forwardIllustrate second-order equation under Simple Harmonic Motion ?arrow_forward
- How are the amplitude, frequency, and phase of a steady-state vibration related to those of the applied harmonic force for an undamped system?arrow_forwardA hang spring oscillates at a frequency of 60 cycles in a minute when an object is attached to it. Calculate the mass of the object if the spring constant is 250 N/m. Kindly show your formula trasformation.arrow_forwardWhat evidence from this graph shows that the spring obeys Hooke’s Law?arrow_forward
- You have just seen how measurements of the period can be used to calculate the spring constant. Suppose you wished to determine the spring constant, but you did not have a stopwatch. Given everything in the simulation, except the stopwatch, how would you determine the spring constant for a new spring? Think back to Hooke’s law, and instead of a measurement of time, use a measurement of distance.arrow_forwardWhat is the general relationship between mass and the elongation of the spring?arrow_forwardWhat is the lagrange's equation for simple pendulum?arrow_forward
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