Chemistry, The Central Science, Volume 1, Custom For Houston Community College
Chemistry, The Central Science, Volume 1, Custom For Houston Community College
19th Edition
ISBN: 9781323850206
Author: Lemay, Bursten Brown, Woodward Murphy, Lufaso Stoltzfus
Publisher: Pearson Higher Ed
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Question
Chapter 16, Problem 1DE

(a)

Interpretation Introduction

To determine: The method of categorization of the sample as acidic or basic.

(a)

Expert Solution
Check Mark

Answer to Problem 1DE

Solution: The method of categorization of the sample as acidic or basic is by using litmus paper.

Explanation of Solution

If the solution is acidic, it changes blue litmus paper into red and there is no change in color for red litmus paper.

If the solution is basic it changes red litmus paper into blue and there is no change in color for blue litmus paper.

Conclusion

The sample is categorized as acidic or basic by using litmus paper.

(b)

Interpretation Introduction

To determine: The method of categorization of the sample as weak acid or strong acid.

(b)

Expert Solution
Check Mark

Answer to Problem 1DE

Solution: The method of categorization of the sample as weak acid or strong acid is titration.

Explanation of Solution

A strong acid and a weak acid can be differentiated by titrating them agianst a strong base like NaOH with the help of two acid-base indicators namely, methyl orange and phenolphthalein. The titre value is noted in both the cases.

When strong acid is titrated agianst a strong base, the same titre value is obtained for both the indicators. For tritration of weak acid and strong base, the color of indicator,methyl orange changes much earlier than the phenolphthalein and two different titre values are obtained.

Conclusion

Thus, the method of categorization of the sample as weak acid or strong acid is titration.

(c)

Interpretation Introduction

To determine: The value of Ka for weak acid.

(c)

Expert Solution
Check Mark

Answer to Problem 1DE

Solution: The value of Ka for weak acid is determined by using pKa value.

Explanation of Solution

The pKa for the pure substance is equal to its pH value.

The value of pKa is calculated by the formula,

pKa=logKa

Rearrange the above equation to calculate the value of Ka .

Ka=antilogpKa

Conclusion

The value of pKa is used to determine Ka .

(d)

Interpretation Introduction

To determine: The method of separation of salt of weak acid.

(d)

Expert Solution
Check Mark

Answer to Problem 1DE

Solution: The method of separation of salt of weak acid is by using the immiscible organic solvent and water.

Explanation of Solution

Weak acids being organic in nature are more soluble in organic solvent.

For the separation of sodium salt of weak acid, the titrated mixture is dissolved in the mixture of immiscible organic solvent and water.

The salt being ionic preferred to dissolved in aqueous layer and weak acid preferred to dissolve in organic layer.

The aqueous layer is separated by separating funnel.

Conclusion

The salt of weak acid is separated by using the immiscible organic solvent and water.

(e)

Interpretation Introduction

To determine: The strength of the base and the Kb value.

(e)

Expert Solution
Check Mark

Answer to Problem 1DE

Solution: The strength of the base and the Kb value is stated below.

Explanation of Solution

The strength of a base is determined by comparing pH paper with pH scale.

If the value of pH of the solution is close to 14 than it is a strong base and if the value of pH of the solution is close to 7 than it is a weak base.

The pKb for the pure substance is equal to its pH value.

The value of pKb is calculated by the formula,

  pKb=logKb

Rearrange the above equation to calculate the value of Kb .

Kb=antilogpKb

Conclusion

The strength of the weak base is determined by using pH paper.

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Chapter 16 Solutions

Chemistry, The Central Science, Volume 1, Custom For Houston Community College

Ch. 16.4 - Practice Exercise 1 A solution at 250C has [OH-] =...Ch. 16.4 - Practice Exercise 2 In a sample of lemon juice,...Ch. 16.4 - Practice Exercise 1 A solution at 25° C has pOH =...Ch. 16.4 - Prob. 16.7.2PECh. 16.5 - Practice Exercise 1 Order the following three...Ch. 16.5 - Prob. 16.8.2PECh. 16.5 - Practice Exercise 1 Order the following three...Ch. 16.5 - Prob. 16.9.2PECh. 16.6 - Prob. 16.10.1PECh. 16.6 - Practice Exercise 2 Niacin, one of the B vitamins,...Ch. 16.6 - Prob. 16.11.1PECh. 16.6 - Practice Exercise 2 A 0.020 M solution of niacin...Ch. 16.6 - Practice Exercise 1 What is the pH of a 0.40 M...Ch. 16.6 - Practice Exercise 2 The Ka for niacin (Sample...Ch. 16.6 - Prob. 16.13.1PECh. 16.6 - Prob. 16.13.2PECh. 16.6 - Practice Exercise 1 What is the pH of a 0.28 M...Ch. 16.6 - Practice Exercise 2 Calculate the pH of a 0.020 M...Ch. 16.7 - Prob. 16.15.1PECh. 16.7 - Practice Exercise 2 Which of the following...Ch. 16.7 - Prob. 16.16.1PECh. 16.7 - Practice Exercise 2 What is the morality of an...Ch. 16.8 - Practice Exercise 1 By using information from...Ch. 16.8 - Practice Exercise 2 Based on information in...Ch. 16.9 - Prob. 16.18.1PECh. 16.9 - Prob. 16.18.2PECh. 16.9 - Practice Exercise 1 How many of the following...Ch. 16.9 - Practice Exercise 2 Predict whether the...Ch. 16.10 - Prob. 16.20.1PECh. 16.10 - In each pair, choose the compound that gives the...Ch. 16 - Prob. 1DECh. 16 - a. Identify the Br ted-Lowry acid and base in the...Ch. 16 - Prob. 2ECh. 16 - Prob. 3ECh. 16 - Prob. 4ECh. 16 - 16.5 The following diagrams represent aqueous...Ch. 16 - Prob. 6ECh. 16 - Which of these statements about how the percent...Ch. 16 - 16.8 Each of the three molecules shown here...Ch. 16 - Prob. 9ECh. 16 - Which of the following diagrams best represent an...Ch. 16 - Prob. 11ECh. 16 - Prob. 12ECh. 16 - Prob. 13ECh. 16 - 16.14 Which of the following statements is...Ch. 16 - Prob. 15ECh. 16 - Prob. 16ECh. 16 - Identify the Bronsted-Lowry acid and the...Ch. 16 - Prob. 18ECh. 16 - Prob. 19ECh. 16 - Prob. 20ECh. 16 - Prob. 21ECh. 16 - Prob. 22ECh. 16 - Prob. 23ECh. 16 - Prob. 24ECh. 16 - Prob. 25ECh. 16 - Prob. 26ECh. 16 - Prob. 27ECh. 16 - Prob. 28ECh. 16 - 16.29 Calcualte [H +] for each of the following...Ch. 16 - Prob. 30ECh. 16 - 16.31 At the freezing point of water (0 o C), K10...Ch. 16 - Prob. 32ECh. 16 - Prob. 33ECh. 16 - Prob. 34ECh. 16 - 16.35 Complete the following table by calculating...Ch. 16 - Prob. 36ECh. 16 - Prob. 37ECh. 16 - 16.38 Carbon dioxide in the atmosphere dissolves...Ch. 16 - Prob. 39ECh. 16 - Prob. 40ECh. 16 - Prob. 41ECh. 16 - Prob. 42ECh. 16 - Prob. 43ECh. 16 - Prob. 44ECh. 16 - Prob. 45ECh. 16 - Prob. 46ECh. 16 - Prob. 47ECh. 16 - Prob. 48ECh. 16 - Prob. 49ECh. 16 - write the chemical equation and the Ka expression...Ch. 16 - Prob. 51ECh. 16 - Prob. 52ECh. 16 - Prob. 53ECh. 16 - Prob. 54ECh. 16 - Prob. 55ECh. 16 - Prob. 56ECh. 16 - Prob. 57ECh. 16 - Prob. 58ECh. 16 - Calculate the pH of each of the following solution...Ch. 16 - Prob. 60ECh. 16 - Prob. 61ECh. 16 - Prob. 62ECh. 16 - Calculate the percent ionization of hydrazoic acid...Ch. 16 - 16.64 Calculate the percent ionization of...Ch. 16 - Prob. 65ECh. 16 - Prob. 66ECh. 16 - Prob. 67ECh. 16 - 16.68 The hypochlorite ion, CIO- , acts as a weak...Ch. 16 - Prob. 69ECh. 16 - Prob. 70ECh. 16 - Calculate the molar concentration of OH- in a...Ch. 16 - 16.72 Calculate the molar concentration of OH- in...Ch. 16 - Prob. 73ECh. 16 - Prob. 74ECh. 16 - Prob. 75ECh. 16 - Prob. 76ECh. 16 - a. Given that Ka for acetic acid is 1.8 10-5 and...Ch. 16 - 16.78 a. Given that Kb for ammonia is 1.8 X 10 -5...Ch. 16 - Prob. 79ECh. 16 - Prob. 80ECh. 16 - Prob. 81ECh. 16 - Pyridinium bromide (C5H5NHBr) is a strong...Ch. 16 - Prob. 83ECh. 16 - Prob. 84ECh. 16 - Prob. 85ECh. 16 - 16.86 An unknown salt is either KBr, NH4 C1, KCN,...Ch. 16 - Prob. 87ECh. 16 - Prob. 88ECh. 16 - 16.89 Based on their compositions and structures...Ch. 16 - Prob. 90ECh. 16 - 16.91 Indicate whether each of the following...Ch. 16 - Prob. 92ECh. 16 - Prob. 93ECh. 16 - Prob. 94ECh. 16 - Prob. 95ECh. 16 - Prob. 96ECh. 16 - Prob. 97ECh. 16 - Prob. 98ECh. 16 - Prob. 99AECh. 16 - Prob. 100AECh. 16 - Prob. 101AECh. 16 - Prob. 102AECh. 16 - Prob. 103AECh. 16 - Prob. 104AECh. 16 - Benzoic acid (C6H5COOH) and aniline (C6H5NH2) are...Ch. 16 - Prob. 106AECh. 16 - Prob. 107AECh. 16 - Prob. 108AECh. 16 - Butyric acid is responsible for the foul smell of...Ch. 16 - Prob. 110AECh. 16 - Prob. 111AECh. 16 - Prob. 112AECh. 16 - 1S.113 Many moderately large organic molecules...Ch. 16 - Prob. 114AECh. 16 - Prob. 115AECh. 16 - Prob. 116IECh. 16 - Prob. 117IECh. 16 - Prob. 118IECh. 16 - Prob. 119IECh. 16 - 16.120 At 50 oC, the ion-product constant for H2...Ch. 16 - Prob. 121IECh. 16 - Prob. 122IECh. 16 - Prob. 123IECh. 16 - Prob. 124IECh. 16 - Prob. 125IECh. 16 - Prob. 126IE
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