   Chapter 16, Problem 21P

Chapter
Section
Textbook Problem

A tiny sphere of mass 8.00 μg and charge −2.80 nC is initially at a distance of 1.60 μm from a fixed charge of +8.50 nC. If the 8.00-mg sphere is released from rest, find (a) its kinetic energy when it is 0.500 μm from the fixed charge and (b) its speed when it is 0.500 μm from the fixed charge.

(a)

To determine
The kinetic energy.

Explanation

Given info: Mass of the sphere (m) is 8.00μg . The charges are q1=8.50nC and q2=2.80nC . Initial distance of the charge from fixed charge is 1.60μm . Final distance is 0.50μm .

Explanation:

The kinetic energy is equal to the change in electric potential energy.

Formula to calculate the kinetic energy is,

KE=keq1q2(1r11r2)

• ke is the coulomb constant.
• r1 is the initial distance of separation.
• r2 is the final distance of separation.

Substitute 8.50 nC for q1 , 2.80nC for q2 , 1.60μm for r1 , 0

(b)

To determine
The speed of the sphere.

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