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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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Chapter
Section
BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

An air-filled parallel-plate capacitor has plates of area 2.30 cm2 separated by 1.50 mm. The capacitor is connected to a 12.0-V battery. (a) Find the value of its capacitance. (b) What is the charge on the capacitor? (c) What is the magnitude of the uniform electric field between the plates?

(a)

To determine
The capacitance.

Explanation

Formula to calculate the capacitance is,

C=κε0Ad

  • ε0 is the permittivity of free space.
  • κ is the dielectric constant.
  • d is the distance of separation between the plates.
  • A is the area of plate.

Substitute 2.30cm2 for A, 1.50 mm for d, 1.0 for κ and 8.85×1012 C2/Nm2 for ε0 .

C=(1.0)(8.85×1012 C2/Nm2)(2

(b)

To determine
The charge.

(c)

To determine
The electric field.

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