   Chapter 16, Problem 31P

Chapter
Section
Textbook Problem

An air-filled parallel-plate capacitor has plates of area 2.30 cm2 separated by 1.50 mm. The capacitor is connected to a 12.0-V battery. (a) Find the value of its capacitance. (b) What is the charge on the capacitor? (c) What is the magnitude of the uniform electric field between the plates?

(a)

To determine
The capacitance.

Explanation

Formula to calculate the capacitance is,

• ε0 is the permittivity of free space.
• κ is the dielectric constant.
• d is the distance of separation between the plates.
• A is the area of plate.

Substitute 2.30cm2 for A, 1.50 mm for d, 1.0 for κ and 8.85×1012 C2/Nm2 for ε0 .

C=(1.0)(8.85×1012 C2/Nm2)(2

(b)

To determine
The charge.

(c)

To determine
The electric field.

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