   Chapter 16, Problem 33P

Chapter
Section
Textbook Problem

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2 and separated by a distance of 1.80 mm. If a 20.0-V potential difference is applied to these plates, calculate (a) the electric field between the plates, (b) the capacitance, and (c) the charge on each plate.

(a)

To determine
The electric field between the plates.

Explanation

Given info: The distance between the plates (d) is 1.80 mm. The area of the plate is 7.60cm2 . The applied potential difference is 20.0 V.

Explanation:

Formula to calculate the electric field between the plates is,

E=ΔVd

• ΔV is the potential difference.

Substitute 20.0 V for ΔV and 1.80 mm for d.

E=20.0V1

(b)

To determine
The capacitance.

(c)

To determine
The charge on each plate.

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