   # Ethanethiol (C 2 H 5 SH; also called ethyl mercaptan) is commonly added to natural gas to provide the “rotten egg” smell of a gas leak. The boiling point of ethanethiol is 35°C and its heat of vaporization is 27.5 kJ/mol. What is the entropy of vaporization for this substance? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 37E
Textbook Problem
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## Ethanethiol (C2H5SH; also called ethyl mercaptan) is commonly added to natural gas to provide the “rotten egg” smell of a gas leak. The boiling point of ethanethiol is 35°C and its heat of vaporization is 27.5 kJ/mol. What is the entropy of vaporization for this substance?

Interpretation Introduction

Interpretation: The boiling point and the heat of vaporization of ethanethiol is given. The entropy of vaporization for this system is to be calculated.

Concept introduction: Entropy is the measure of degree of disorder or randomness. The value of ΔSvap is calculated using the formula,

ΔSvap=ΔHvapTb

### Explanation of Solution

Given

The normal boiling point of ethanethiol is 35°C .

Heat of vaporization of ethanethiol is 27.5kJ/mol .

The conversion of degree Celsius (°C) into Kelvin (K) is done as,

T(K)=T(°C)+273

Hence,

The conversion of 35°C into Kelvin is,

T(K)=T(°C)+273T(K)=(35+273)K=308K

The conversion of kilo-joule (kJ) into joule (J) is done as,

1kJ=103J

Hence,

The conversion of 27.5kJ into joule is,

27.5kJ=(27

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