   # For mercury, the enthalpy of vaporization is 58.51 kJ/mol and the entropy of vaporization is 92.92 J/K mol. What is the normal boiling point of mercury? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 38E
Textbook Problem
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## For mercury, the enthalpy of vaporization is 58.51 kJ/mol and the entropy of vaporization is 92.92 J/K mol. What is the normal boiling point of mercury?

Interpretation Introduction

Interpretation: The entropy of vaporization and heat of vaporization of Mercury is given. The normal boiling point for this system is to be calculated.

Concept introduction: Entropy is the measure of degree of disorder or randomness. The value of ΔSvap is calculated using the formula,

ΔSvap=ΔHvapTb

### Explanation of Solution

Given

Entropy of vaporization of Mercury is 92.92J/Kmol .

Heat of vaporization of Mercury is 58.51kJ/mol .

The conversion of kilo-joule (kJ) into joule (J) is done as,

1kJ=103J

Hence,

The conversion of 58.51kJ into joule is,

58.51kJ=(58.51×103)J=58510J

Formula

The value of ΔSvap is calculated using the formula,

ΔSvap=ΔHvapTb

Where,

• ΔHvap is the heat of vaporization

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