   # For ammonia (NH 3 ), the enthalpy of fusion is 5.65 kJ/mol and the entropy of fusion is 28.9 J/K mol. a. Will NH 3 (s) spontaneously melt at 200. K? b. What is the approximate melting point of ammonia? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 39E
Textbook Problem
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## For ammonia (NH3), the enthalpy of fusion is 5.65 kJ/mol and the entropy of fusion is 28.9 J/K mol.a. Will NH3(s) spontaneously melt at 200. K?b. What is the approximate melting point of ammonia?

(a)

Interpretation Introduction

Interpretation: The entropy of vaporization and enthalpy of vaporization of Ammonia is given. If Ammonia spontaneously melts at 200K is to be predicted. The approximate melting point of Ammonia is to be calculated.

ΔG=ΔHTΔS

A reaction is said to be spontaneous if the value of ΔG is negative.

### Explanation of Solution

Given

Enthalpy of fusion of Ammonia is 5.65kJ/mol .

Entropy of fusion of Ammonia is 28.9J/Kmol .

The conversion of kilo-joule (kJ) into joule (J) is done as,

1kJ=103J

Hence,

The conversion of 5.65kJ into joule is,

5.65kJ=(5.65×103)J=5650J

Formula

The formula of ΔG is,

ΔG=ΔHTΔS

Where,

• ΔH is the enthalpy of reaction

(b)

Interpretation Introduction

Interpretation: The entropy of vaporization and enthalpy of vaporization of Ammonia is given. If Ammonia spontaneously melts at 200K is to be predicted. The approximate melting point of Ammonia is to be calculated.

ΔG=ΔHTΔS

A reaction is said to be spontaneous if the value of ΔG is negative.

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