   # Predict the sign of ∆S ° and then calculate ∆S ° for each of the following reactions. a. H 2 ( g ) + 1 2 O 2 ( g ) → H 2 O( l ) b. 2CH 3 OH( g ) + 3O 2 ( g ) → 2CO 2 ( g ) + 4H 2 O( g ) c. HCl( g ) → H + ( aq ) + Cl − ( aq ) ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 46E
Textbook Problem
1 views

## Predict the sign of ∆S° and then calculate ∆S° for each of the following reactions.a. H2(g) + 1 2 O2(g) → H2O(l)b. 2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(g)c. HCl(g) → H+(aq) + Cl− (aq)

(a)

Interpretation Introduction

Interpretation: The sign and value of ΔS is to be predicted in each case.

Concept introduction: Entropy (ΔS) is the measure of degree of disorder or randomness. Increase in the randomness of the system leads to increase in the entropy (entropy is positive).  The sign of entropy depends on the number of moles. If number of moles decreases, then sign of the entropy will be negative whereas, if the number of moles increases, the sign of entropy will be positive.

### Explanation of Solution

The stated reaction is,

H2(g)+12O2(g)H2O(l)

The degree of disorder (randomness) decreases during the conversation of gaseous state into liquid state.

Since, decrease in the randomness of the system leads to decrease in the entropy (entropy becomes negative). Hence, the sign of ΔS for the given reaction will be negative.

The value of ΔS(J/Kmol) for the given reactant and product is,

 Molecules ΔS∘(J/K⋅mol) O2(g) 205 H2(g) 131 H2O(g) 189

The formula of ΔS is,

ΔS=npΔS(product)nfΔS(reactant)

Where,

• ΔS is the standard entropy of reaction

(b)

Interpretation Introduction

Interpretation: The sign and value of ΔS is to be predicted in each case.

Concept introduction: Entropy (ΔS) is the measure of degree of disorder or randomness. Increase in the randomness of the system leads to increase in the entropy (entropy is positive).  The sign of entropy depends on the number of moles. If number of moles decreases, then sign of the entropy will be negative whereas, if the number of moles increases, the sign of entropy will be positive.

(c)

Interpretation Introduction

Interpretation: The sign and value of ΔS is to be predicted in each case.

Concept introduction: Entropy (ΔS) is the measure of degree of disorder or randomness. Increase in the randomness of the system leads to increase in the entropy (entropy is positive).  The sign of entropy depends on the number of moles. If number of moles decreases, then sign of the entropy will be negative whereas, if the number of moles increases, the sign of entropy will be positive.

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