(a)
To find: The value of y.
The value of y is 45 in .
Given:
The given figure is,
Figure (1)
The area of figure is 120 in2 .
Calculation:
Tabulate the given information into the language of algebra.
Model the equation for the above information.
Area of part 1+Area of part 2=Total areay×y2+y×y=120
Simplify the above equation for y.
y22+y2=120y2+2y2=2403y2=240y=45
Thus, the value of y is 45 in .
(b)
The value of y is 5 in.
Figure (2)
The area of figure is 1200 cm2 .
Area of part 1+Area of part 2=Total areay×y2+y×1=1200
y22+y=1200y2+2y=2400y2+2y−2400=0
Further simplify the above equation.
(y+50)(y−48)=0y=−50,y=48
The value of x cannot be negative.
Thus, the value of y is 48 cm.
Precalculus: Mathematics for Calculus - 6th Edition