   Chapter 16, Problem 46P

Chapter
Section
Textbook Problem

(a) Find the equivalent capacitance between points a and b for the group of capacitors connected as shown in Figure P16.46 if C1 = 5.00 μF, C2 = 10.00 μF, and C3 = 2.00 μF. (b) If the potential between points a and b is 60.0 V, what charge is stored on C5? Figure P16.46

(a)

To determine
The equivalent capacitance.

Explanation

The capacitors C1 and C2 are connected in series combination. The equivalent capacitance is,

Cs=C1C2C1+C2

At the bottom loop, C2 and C2 are parallel. Therefore,

Cpb=C2+C2=2C2

At the top, the capacitances Cs , Cs and C3 are in parallel combination. The equivalent capacitance is,

Ceqt=Cs+Cs+C3

Therefore,

Ceqt=2C1C2C1+C2+C3

Cpb and Ceqt are in series connection. The total equivalent capacitance is,

Ceq=CpbCeqtCpb+Ceqt

Therefore,

Ceq=[2C1C2+C1C3+C2C3][2C2]4C1C2+C1C3+C2C3+2C22

Substitute 5

(b)

To determine
The charge on C3 .

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