BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

Will a precipitate form when 100.0 mL of 4.0 × 10−4 M Mg(NO3)2 is added to 100.0 mL of 2.0 × 10−4 M NaOH?

Interpretation Introduction

Interpretation: The concentration and volume of Mg(NO3)2 and NaOH is given. The formation of a precipitate, when the given amount of Mg(NO3)2 is added to NaOH solution is to be validated.

Concept introduction: The formation of a solid in a solution is known as precipitation.

Solubility product, Ksp is defined as the concentration of ions in a saturated solution where each ion is raised to the power of their coefficients. Ion product, Q is defined as the initial concentration of ions in any solution where each ion is raised to the power of their coefficients.

The relation between ion product, Q and solubility product, Ksp is as follows.

If Ksp>Q , then no precipitate will form.

If Ksp<Q , then precipitate will form.

If Ksp=Q , then no precipitate will form.

Explanation

Explanation

To determine: If the formation of a precipitate takes place when the given amount of Mg(NO3)2 is added to NaOH .

The solubility product of Mg(OH)2 is 1.6×1011_ .

Given

Concentration of Mg(NO3)2 is 4.0×104M .

Concentration of NaOH is 2.0×104M .

The Mg(OH)2 is the only precipitate formed during mixing of 100mL NaOH and 100mL of Mg(NO3)2 if,

Ksp<Q

The reaction of Mg(NO3)2 and Mg(NO3)2 is,

Mg(NO3)2+NaOHMg(OH)2+NaNO3

Formula

The solubility product of Mg(OH)2 is calculated as,

Ksp=[Mg2+][OH]2

Where,

Ksp is the solubility product.

[Mg2+] is the concentration of Mg2+ .

[OH] is the concentration of OH .

Substitute the value of [OH] and [Mg2+] in the above expression.

Ksp=[Mg2+][OH]2=(4.0×104)(2.0×104)2=1.6×1011_

The initial concentration of Mg2+ is 2.0×104M_ and initial concentration of OH is 1.0×104M_ .

Given

Concentration of Mg(NO3)2 is 4.0×104M .

Concentration of NaOH is 2.0×104M .

Volume of NaOH is 100mL .

Volume of Mg(NO3)2 is 100mL .

It is assumed that the concentration of Mg2+ and OH is same as the concentration of Mg(NO3)2 and NaOH . Hence, concentration of Mg2+ and OH is,

[Mg2+]=4.0×104M[OH]=2.0×104M

Formula

The initial concentration of compound is calculated using the formula,

Initialconcentration=Volumeofcompound(mL)×Givenconcentration(Volumeoforiginalsolution(mL)+(Volumeofcompoundadded(mL))) (1)

Substitute the values of volume, given concentration of Mg2+ and volume of original solution in the above equation

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

Partially completed proteins are not held for completion at a later time when the diet may improve. T F

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

How is optimal foraging adaptive?

Biology (MindTap Course List)

25. Name each compound:

Chemistry In Focus

What are sister chromatids?

Human Heredity: Principles and Issues (MindTap Course List)

What gives amino acids their individual properties?

Biology: The Dynamic Science (MindTap Course List)

Anticodons pair with ___ . a. mRNA codons b. DNA codons c. RNA anticodons d. amino acids

Biology: The Unity and Diversity of Life (MindTap Course List)