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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A 12.0 V battery is connected to a 4.50 μF capacitor. How much energy is stored in the capacitor?

To determine
The energy stored in the capacitor.

Explanation

Given info: The capacitance is 4.50μF . The potential difference applied by the battery is 12.0 V.

Explanation:

Formula to calculate the energy stored is,

E=12C(ΔV)2

  • C is the capacitance.
  • ΔV is the potential difference.

Substitute 4.50μF for C and 12.0 V for ΔV

E=12(4.50μF)(12

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