Chapter 16, Problem 50PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# A 0.015M solution of a base has a pH of 10.09 a) What are the hydronium and hydroxide ion concentrations of this solution? b) Is the base a strong base, a moderately weak base (Ka of about 10‒5) or a very weak base (Kb of about 10‒10)?

(a)

Interpretation Introduction

Interpretation: The hydronium and hydroxide ion concentration of the solution has to be calculated.

Concept introduction:

Equilibrium constants:

The equilibrium constant is used to quantitative measurement of the strength of the acid and bases in the water.

Ka is acid constant for equilibrium reactions.

HA + H2OH3O++ A-Ka[H3O+][A-][HA]

Kb is a base constant for equilibrium reaction.

BOH + H2OB++ OH-Ka[B+][OH-][BOH]

Stronger acids have larger Ka value and stronger bases have larger Kb values.

To calculate the hydronium ion concentration and hydroxide ion concentration by using following formula.

pH + pOH=14

Explanation

pHÂ =Â -log[H3O+]TheÂ givenÂ pHÂ =Â 10.09Â 10.09Â =Â Â -log[H3O+][H3O+]=Â 8.1Ã—10-11WeÂ know,pHÂ +Â pOHÂ =14.00pHÂ =10.09Â Â Â Â Â Â Â Â Â pOHÂ =14Â -Â 10.09Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â =3

(b)

Interpretation Introduction

Interpretation:

The ionization constant (Kb) of an unknown base has to be calculated. and the base is a strong base or a moderately weak base or very weak base also to be identified.

Concept introduction:

Equilibrium constants:

The equilibrium constant is used to quantitative measurement of the strength of the acid and bases in the water.

Ka is acid constant for equilibrium reactions.

HA + H2OH3O++ A-Ka[H3O+][A-][HA]

Kb is base constant for equilibrium reaction.

BOH + H2OB++ OH-Ka[B+][OH-][BOH]

Stronger acids have larger Ka value and stronger bases have larger Kb values.

To calculate the hydronium ion concentration and hydroxide ion concentration by using following formula.

pH + pOH=14

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