# The amount of 60% acid solution, if it is mixed with a 30% solution to produce 300 mL of a 50% solution.

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.6, Problem 53E
To determine

## To find: The amount of 60% acid solution, if it is mixed with a 30% solution to produce 300 mL of a 50% solution.

Expert Solution

The amount of 60% acid solution is 200 mL.

### Explanation of Solution

A 60% acid solution mixed with a 30% solution to produce 300 mL of a 50% solution.

Let x be the amount of 60% acid solution.

Tabulate the given information algebraically.

 In words In Algebra Amount of 60% solution x Amount of 30% solution 300−x

Model the equation for the above information as follows.

60%ofacidsolution+30%ofacidsolution=50%of300mL60x+30(300x)=300×50

On further simplification,

60x+900030x=1500030x=15000900030x=6000x=200

Thus, the amount of 60% acid solution is 200 mL.

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