   Chapter 16, Problem 54P

Chapter
Section
Textbook Problem

(a) How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 5.00 cm2? (b) Find the maximum charge if polystyrene is used between the plates instead of air. Assume the dielectric strength of air is 3.00 × 106 V/m and that of polystyrene is 24.0 × 106 V/m.

(a)

To determine
The charge on capacitor.

Explanation

Given info: The maximum dielectric strength is 3.00×103V/m . The area of the plate is 5.00cm2 .

Explanation:

Formula to calculate the charge on capacitor is,

Q=κairε0AE

• κair is the dielectric constant of air.
• ε0 is the permittivity of free space.
• A is the area of the plate.
• E is the dielectric strength.

Substitute 8.85×1012 m3kg1s4A2 for ε0 , 1.0 for κair , 5

(b)

To determine
The charge on capacitor when the dielectric is polystyrene.

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