# The amount of pure silver added to the mixture.

BuyFind

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.6, Problem 55E
To determine

Expert Solution

## Answer to Problem 55E

The amount of pure silver is 18 g.

### Explanation of Solution

Given:

A jeweler has 5 rings and weight of each ring is 18 g made an alloy of 10% silver and 90% gold. Rings melted down and add more silver should be added to reduce the gold content to 75%.

Calculation:

Let the amount of pure silver be x.

Weight of five rings,

Weight=5×Weightofonering=5×18=90

Weight of five rings is 90 g.

Tabulate the given information into the language of algebra.

 In words In Algebra Amount of pure silver x Amount of total mixture x+90 Amount of silver in five rings 0.10(90) Amount of silver in total mixture 0.25(x+90)

Model the equation for the above information.

(Amountofsilverinrings)+(Amountofpuresilver)=(Amountofsilverinmixture)0.10(90)+x=0.25(x+90)

Simplify the above equation for x,

9+x=0.25x+22.5x0.25x=13.50.75x=13.5x=18

Thus, the amount of pure silver is 18 g.

### Have a homework question?

Subscribe to bartleby learn! Ask subject matter experts 30 homework questions each month. Plus, you’ll have access to millions of step-by-step textbook answers!