BuyFind

Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805
BuyFind

Single Variable Calculus: Concepts...

4th Edition
James Stewart
Publisher: Cengage Learning
ISBN: 9781337687805

Solutions

Chapter 1.6, Problem 56E

(a)

To determine

To find: The domain of the function.

Expert Solution

Answer to Problem 56E

The domain of the function is x0.368 .

Explanation of Solution

Given information:

The given function is,

  f(x)=ln(2+lnx)

Consider the graph of the given function,

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 1.6, Problem 56E , additional homework tip  1

From the graph, the domain of the given function is x0.368 .

(b)

To determine

To find: The inverse and the domain of the inverse function.

Expert Solution

Answer to Problem 56E

The inverse of the function is f1(x)=e(2ex) and the domain is all real numbers.

Explanation of Solution

Given information:

The given function is,

  f(x)=ln(2+lnx)

The inverse of the function is calculated as,

  f(x)=ln(2+lnx)y=ln(2+lnx)ey=2+lnxlnx=2ey

Simplify further,

  x=e(2ey)

For the inverse function, replace x and y ,

  y=e(2ex)f1(x)=e(2ex)

Consider the graph of the inverse function,

  Single Variable Calculus: Concepts and Contexts, Enhanced Edition, Chapter 1.6, Problem 56E , additional homework tip  2

From the graph, the domain of the given function is 1.414x1.414 .

Thus, the inverse of the function is f1(x)=e(2ex) and the domain is all real numbers.

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