   # Given the following data: 2 C 6 H 6 ( l ) + 15 O 2 ( g ) → 12 CO 2 ( g ) + 6 H 2 O ( l ) Δ G ∘ = − 6399 KJ C ( s ) +O 2 ( g ) → CO 2 ( g ) Δ G ∘ = − 394 KJ H 2 ( g ) + 1 2 O 2 ( g ) → H 2 O ( l ) Δ G ∘ = − 237 K J calculate ∆G ° for the reaction 6 C ( s ) + 3 H 2 ( g ) → C 6 H 6 ( l ) ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 58E
Textbook Problem
1 views

## Given the following data: 2 C 6 H 6 ( l ) + 15 O 2 ( g ) → 12 CO 2 ( g ) + 6 H 2 O ( l )       Δ G ∘ = − 6399 KJ C ( s ) +O 2 ( g ) → CO 2 ( g )     Δ G ∘ = − 394 KJ H 2 ( g ) + 1 2 O 2 ( g ) → H 2 O ( l )     Δ G ∘ = − 237 K J calculate ∆G° for the reaction 6 C ( s ) + 3 H 2 ( g )   → C 6 H 6 ( l )

Interpretation Introduction

Interpretation: The standard free energy change for the given reaction with the values of standard free energy change of individual reactions is to be calculated.

Concept Introduction: The standard free energy change of the given reaction is the summation of the free energy change of individual reactions.

To determine: The standard free energy change of the given reaction.

### Explanation of Solution

Given

The first individual reaction is,

2C6H6(l)+15O2(g)12CO2(g)+6H2O(l)ΔG=6399kJ (1)

The second individual reaction is,

C(s)+O2(g)CO2(g)ΔG=394kJ (2)

The third individual reaction is,

H2(g)+12O2(g)H2O(l)ΔG=237kJ (3)

The reaction with unknown free energy change is,

6C(s)+3H2(g)C6H6(l) (4)

Add the equation (2) multiplied with 6 and (3) multiplied with 3 and subtract equation (1) divided by 2 from it to get the required reaction

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