# The amount of solution drained and replaced with bleach.

BuyFind

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.6, Problem 58E
To determine

Expert Solution

## Answer to Problem 58E

The amount of solution drained and replaced with bleach is 3.06 gallons.

### Explanation of Solution

Given:

The sterilization tank contains 100 gal of solution of 2% ordinary household bleach. New concentration of bleach should be 5% for complete sterilization.

Calculation:

Let the amount of solution drain and replace with bleach be x.

Tabulate the given information into the language of algebra.

 In words In Algebra Amount of replaced bleach x Amount of 2% bleach 0.02(100−x) Amount of 5% bleach 0.05(100)

Model the equation for the above information.

(Amountofbleachfor5%sterlization)=(Amountofbleachfor2%sterlization)+(Amountofbleachadddedintank)0.05(100)=(0.02)(100x)+1(x)

Simplify the above equation for x,

20.02x+x=52+0.98x=50.98x=3x=3.06

Thus, the amount of solution drained and replaced with bleach is 3.06 gallons.

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