# A constant electric field accelerates a proton from rest through a distance of 2.00 m to a speed of 1.50 × 10 5 m/s. (a) Find the change in the proton’s kinetic energy. (b) Find the change in the system’s electric potential energy. (c) Calculate the magnitude of the electric field.

### College Physics

11th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305952300

### College Physics

11th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305952300

#### Solutions

Chapter
Section
Chapter 16, Problem 5P
Textbook Problem

## A constant electric field accelerates a proton from rest through a distance of 2.00 m to a speed of 1.50 × 105 m/s. (a) Find the change in the proton’s kinetic energy. (b) Find the change in the system’s electric potential energy. (c) Calculate the magnitude of the electric field.

Expert Solution

(a)

To determine
The kinetic energy of proton.

### Explanation of Solution

Given info: The displacement of the proton (x) is 2.00 cm. The velocity of the proton (v) is 1.50×105m/s .

Explanation:

Formula to calculate the kinetic energy is,

KE=12mv2

• m is the mass of the proton.

Substitute 1.67×1027kg for m and 1.50×105m/s for v.

KE=12(1

Expert Solution

(b)

To determine
The change in potential energy.

Expert Solution

(c)

To determine
The magnitude of electric field.

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