   Chapter 16, Problem 5P

Chapter
Section
Textbook Problem

A constant electric field accelerates a proton from rest through a distance of 2.00 m to a speed of 1.50 × 105 m/s. (a) Find the change in the proton’s kinetic energy. (b) Find the change in the system’s electric potential energy. (c) Calculate the magnitude of the electric field.

(a)

To determine
The kinetic energy of proton.

Explanation

Given info: The displacement of the proton (x) is 2.00 cm. The velocity of the proton (v) is 1.50×105m/s .

Explanation:

Formula to calculate the kinetic energy is,

KE=12mv2

• m is the mass of the proton.

Substitute 1.67×1027kg for m and 1.50×105m/s for v.

KE=12(1

(b)

To determine
The change in potential energy.

(c)

To determine
The magnitude of electric field.

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