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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.00 and whose dielectric strength is 2.00 × 108 V/m. The desired capacitance is 0.250 μF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates.

To determine
The minimum area of plates.

Explanation

Given info: The dielectric constant ( κ ) is 3.00. The dielectric strength (E) is 2.00×108V/m . The potential difference ( ΔV ) is 4.00×103V .

Formula to calculate the capacitance is,

C=κε0AEΔV

On Re-arranging,

A=C(ΔV)κε0E

Substitute 8.85×1012m3kg1s4A2 for ε0 , 4.00×103V for ΔV , 2

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