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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

Find the equivalent capacitance of the group of capacitors shown in Figure P16.65.

images

Figure P16.65

To determine
The equivalent capacitance.

Explanation

The capacitors 5.00μF and 4.00μF in parallel. Therefore,

Cp1=(5.00μF)+(4.00μF)=9.00μF

The capacitors 2.00μF , 3.00μF and 7.00μF in parallel. Therefore,

Cp2=(2.00μF)+(3.00μF)+(7.00μF)=12.0μF

The capacitors Cp1 and 3.00μF in series. Therefore,

C1=Cp1(3.00μF)Cp1+(3.00μF)=(9.00μF)(3.00μF)(9.00μF)+(3.00μF)=2

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