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ChemistryChemistry9th Edition

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Chapter 16, Problem 67E
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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

The overall formation constant for HgI42− is 1.0 × 1030. That is,

1.0   ×   10 30   =   [ H g I 4 2 − ] [ H g 2 + ] [ I − ] 4

What is the concentration of Hg2+ in 500.0 mL of a solution that was originally 0.010 M Hg2+ and 0.78 M I−? The reaction is

Hg 2+ ( a q )   +   4 I − ( a q )   ⇌   H g I 4 2 − ( a q )

Interpretation Introduction

Interpretation: The combination reaction of Hg2+ and I− , the overall formation constant of HgI42− and concentration of Hg2+, I− before the reaction is given. The concentration of Hg2+ in the given volume of a solution is to be calculated.

Concept introduction: At equilibrium, the equilibrium constant expression is expressed by the formula,

K=Concentration of productsConcentration of reactants

Explanation

To determine: The concentration of Hg2+ in 500 mL of the given solution.

Given

Concentration of Hg2+ before reaction is 0.010 M .

Concentration of I− before reaction is 0.78 M .

The overall formation constant for HgI42− is 1.0×1030 .

The reaction that takes place is,

Hg2+(aq)+4I−(aq)⇌HgI42−(aq)

The reaction is assumed to be completed. The net reaction is,

Hg2++4I−→HgI42−Before reaction0.010 M0.78 M0Afterreaction00.78−(4×0.010)=0

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