   Chapter 16, Problem 68AP

Chapter
Section
Textbook Problem

When a certain air-filled parallel-plate capacitor is connected across a battery, it acquires a charge of 150. μC on each plate. While the battery connection is maintained, a dielectric slab is inserted into, and fills, the region between the plates. This results in the accumulation of an additional charge of 200. μC on each plate. What is the dielectric constant of the slab?

To determine
The dielectric constant of the slab.

Explanation

Given info: The initial charge ( Q1 ) is 150μF . The additional charge ( Q2 ) is 200μF .

Explanation:

Formula to calculate the capacitance is,

C=Q1ΔV

Formula to calculate the new capacitance is,

Cnew=Q1+Q2ΔV

Formula to calculate the dielectric constant,

κ=CnewC

Therefor

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