BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.6, Problem 71E
To determine

To find: The speed of vehicle from Ajax to Barrington.

Expert Solution

Answer to Problem 71E

The speed of vehicle from Ajax to Barrington is 50 mi/h or 240 mi/h.

Explanation of Solution

Given:

The distance from Ajax to Barrington is 120 mi and distance between Barrington to Collins is 150 mi.

Salesman increases his speed by 10 mi/h in his second leg and in second leg he take 6 min more than first leg.

Formula used:

Distance formula is,

distance=time×rate

Calculation:

Let the speed of vehicle from Ajax to Barrington be x ft/s.

Tabulate the given information into the language of algebra.

Distance Speed Time
Ajax to Barrington 120 x 120x
Barrington to Collins 150 x+10 150x+10

Model the equation for the above information.

(timefromBarringtontoCollins)(timefromAjaxtoBarrington)=moretime150x+10120x=660

Simplify the above equation for x,

150x120(x+10)=110x(x+10)(MultiplybyLCDx(x+10))1500x1200(x+10)=x(x+10)1500x1200x12000=x2+10xx2290x+12000=0

Factor the above equation.

(x50)(x240)=0x=50,x=240

Thus, the speed of vehicle from Ajax to Barrington is 50 mi/h or 240 mi/h.

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