   # The local anaesthetic novocaine is the hydrogen chloride salt of an organic base, procaine. C 13 H 20 N 2 O 2 (aq) + HCl(aq) → [HC 13 H 20 N 2 O 2 ] + Cl − (aq) The p K a for novocaine is 8.85. What is the pH of a 0.0015M solution of novocaine? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 16, Problem 93GQ
Textbook Problem
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## The local anaesthetic novocaine is the hydrogen chloride salt of an organic base, procaine. C 13 H 20 N 2 O 2 (aq) + HCl(aq)  →  [HC 13 H 20 N 2 O 2 ] + Cl − (aq) The pKa for novocaine is 8.85. What is the pH of a 0.0015M solution of novocaine?

Interpretation Introduction

Interpretation:

The pH of a 0.0015M solution of novocaine has to be calculated.

Concept introduction:

Equilibrium constants:

The equilibrium constant is used to quantitative measurement of the strength of the acid and bases in the water.

Ka: It is an acid constant for equilibrium reactions.

HA + H2OH3O++ A-Ka[H3O+][A-][HA]

Kb: It is a base constant for equilibrium reaction.

BOH + H2OB++ OH-Ka[B+][OH-][BOH]

Ion product constant for wter  Kw= [H3O+][OH-]       =1.00×10-14 pH = -log[H3O+]pOH= -log[OH-]

Relation between pH and pOH

pH + pOH =14

### Explanation of Solution

The given PKa of novocaine is 8.85.

Let’s calculate the Ka of novocaine.

Pka= -logKaPka= 8.85Ka= -log(8.85)= 1.4×10-9

Therefore,

Ka=1.4×10-9

The chemical equilibrium reaction is as follows.

[HC13H20N2O2]+ (aq) + H2O(l) H3O+(aq) + C13H20N2O2

Equilibrium expression:

Ka[H3O+][C13H20N2O2][HC13H20N2O2]+

The initial concentration of is 0.0015M.

Enter the ICE table the concentrations before equilibrium is established, the change that occurs as the reaction proceeds to equilibrium and the concentrations when equilibrium has been achieved.

[HC13H20N2O2]+ (aq) + H2O(l) H3O+(aq) + C13H20N2O2I         0.0015M                        --                    --                      --C           -x                                --                   + x                  + xE        (0

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