   Chapter 16, Problem 9P

Chapter
Section
Textbook Problem

An ionized oxygen molecule (O+2) at point A has charge +e and moves at 2.00 × 103 m/s in the positive x-direction. A constant electric force in the negative x-direction slows the molecule to a stop at point B, a distance of 0.750 mm past A on the x-axis. Calculate (a) the x-component of the electric field and (b) the potential difference between points A and B.

(a)

To determine
The x component of electric field.

Explanation

Given info: The speed of the molecule is 2.00×103m/s . The charge of the molecule is e. The displacement (d) is 0.750 mm.

Explanation:

Formula to calculate the potential difference is,

E=KEed

• KE is the kinetic energy

The kinetic energy is,

KE=12mv2

• m is the mass of the molecule.
• v is the speed of the molecule.

From the above equations,

E=mv22ed

Substitute 1.6×1019C for e, 2.00×103m/s for v, 0.750 mm for d and 5.32×1026kg for m.

E=(5.32×1026kg)(2

(b)

To determine
The potential difference between A and B.

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