   Chapter 16.10, Problem 1.1ACP

Chapter
Section
Textbook Problem

If a fatal does of atropine is 100. mg. what amount of compound (moles) is this?

Interpretation Introduction

Interpretation:

Determine the number of moles (amount) present in the 100 mg of atropine.

Concept introduction:

Molarity:

Molarity is defined as the amount of mole of a compound dissolved in an amount of solvent.

Molarity = moles solutelitres of solution

Number of moles = m (g)Mm = Given mass in gramsM = molar mass in grams/mole

Explanation

From the given data,

The given mass of Atropine = 100 mg = 0.1 g

Molar mass of Atropine = 289.369 g/mol

Number of moles = m(g)<

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