   # What is the p K 2 for the conjugate acid of ammonia? (a) 4.74 (b) 9.25 (c) 5.60 (d) 7.00 ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 16.3, Problem 4RC
Textbook Problem
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## What is the pK2 for the conjugate acid of ammonia? (a) 4.74 (b) 9.25 (c) 5.60 (d) 7.00

Interpretation Introduction

Interpretation:

The ammonia ( NH3 ) molecule pKa value should be calculate and identified.

Concept introduction:

pKa: It is introduced as an index to express the acidity of weak acids, where pKa is defined as fallows, we consider the Ka constant for acetic acid 1.8×105(pKa) but pKa constant for is 4.8 which is a simpler expression. Furthermore the smaller pKa value has strongest acid.

In aqueous solution an acid undergoes ionization. The ionization of an acid is can be expressed in terms of equilibrium constant. The quantitative measurement tells about the strength of the acid. Higher the value of Ka stronger will be the acid. The acid dissocition can be represented as following equilibrium,

HA(aq)+  H2O(l) H3O+(aq)+ A1(aq)

The dissociation constant for the acid is Ka ,

Ka=[H3O+][A][HA]

For simplifications pKa value is used to find the acidic strength of acid. Which is calculated by taking negative logarithm of Ka .

pKa=log(Ka)

The lower value of pKa of an acid, stronger will be the acid. Thus on comparing the pKa value it can be determined which acid is stronger one among them.

### Explanation of Solution

The pKa value of Ammonia calculation method given below

ThepKavalueofammoniamoleculeTheKbofammonia=1.8×105ButpKb=logKbpKb=log(1.8×105)pKb=4

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