Chemistry & Chemical Reactivity

10th Edition

John C. Kotz + 3 others

ISBN: 9781337399074

Solutions

Chapter

Section

Chemistry & Chemical Reactivity

10th Edition

John C. Kotz + 3 others

ISBN: 9781337399074

Textbook Problem

What are the equilibrium concentrations of acetic acid, the acetate ion, and H₃O⁺ for a 0.10 M solution of acetic acid (K₂ = 1.8 × 10⁻⁵)? What is the pH of the solution?

Interpretation Introduction

Interpretation:

Equilibrium concentration of acetic acid, acetate ion, H3O+ and pH of 0.10M solution of acetic acid is to be determined

Concept introduction:

The pH of a solution of acetic acid can be calculated by using the hydronium ion concentration by using the expression, pH=−log[H3O+].

Hydronium ion concentration is calculated by considering the equilibrium conditions and from the value of acid dissociation constant.

The concentration of acetic acid and acetate ion is determined by using equilibrium condition The concentration of acetate ion and hydronium ion is equal at equilibrium according to the reaction stoichiometry.

Equilibrium constants:

The equilibrium constant is used to quantitative measurement of the strength of the acid and bases in the water.

Ka is an acid constant for equilibrium reactions.

HA + H2O⇌H3O++ A-Ka= [H3O+][A-][HA]

Kb is a base constant for equilibrium reaction.

BOH + H2O⇌B++ OH-Ka= [B+][OH-][BOH]

Explanation

Calculate concentrations of all ions in the solution and pH of 0.10M solution of acetic acid from the given data.

Given data

The initial concentration of the acetic acid solution is 0.10M.

The acid dissociation constant Ka of acetic acid is 1.8×10−5.

The ICE table for the dissociation of acetic acid is given below,

EquilibriumCH3COOH(aq)⇄CH3COO−(aq)+H3O+(aq)Initial(M)0.1000Change(M)−x+x+xEquilibrium(M)0.10−xxx

From ICE table the expression for Ka;

Ka=[CH3COO−][H3O+][CH3COOH]

Substituting equilibrium concentrations for acetate ion, hydronium ion, and acetic acid;

Ka=x2(0.1−x)

Substituting the value of acid dissociation constant (Ka) in the above equation,

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Chapter 16 Solutions

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Sect-16.2 P-16.1CYU Sect-16.4 P-16.2CYU Sect-16.5 P-16.3CYU Sect-16.7 P-16.4CYU Sect-16.7 P-16.5CYU Sect-16.7 P-16.6CYU Sect-16.7 P-16.7CYU Sect-16.7 P-16.8CYU Sect-16.8 P-16.9CYU Sect-16.10 P-1.1ACP

Sect-16.10 P-1.2ACP Sect-16.10 P-1.3ACP Sect-16.10 P-2.1ACP Sect-16.10 P-2.2ACP Sect-16.10 P-2.3ACP Sect-16.10 P-2.4ACP Sect-16.10 P-2.5ACP Ch-16 P-1PS Ch-16 P-2PS Ch-16 P-3PS Ch-16 P-4PS Ch-16 P-5PS Ch-16 P-6PS Ch-16 P-7PS Ch-16 P-8PS Ch-16 P-9PS Ch-16 P-10PS Ch-16 P-11PS Ch-16 P-12PS Ch-16 P-13PS Ch-16 P-14PS Ch-16 P-15PS Ch-16 P-16PS Ch-16 P-17PS Ch-16 P-18PS Ch-16 P-19PS Ch-16 P-20PS Ch-16 P-21PS Ch-16 P-22PS Ch-16 P-23PS Ch-16 P-24PS Ch-16 P-25PS Ch-16 P-26PS Ch-16 P-27PS Ch-16 P-28PS Ch-16 P-29PS Ch-16 P-30PS Ch-16 P-31PS Ch-16 P-32PS Ch-16 P-33PS Ch-16 P-34PS Ch-16 P-35PS Ch-16 P-36PS Ch-16 P-37PS Ch-16 P-38PS Ch-16 P-39PS Ch-16 P-40PS Ch-16 P-41PS Ch-16 P-42PS Ch-16 P-43PS Ch-16 P-44PS Ch-16 P-45PS Ch-16 P-46PS Ch-16 P-47PS Ch-16 P-48PS Ch-16 P-49PS Ch-16 P-50PS Ch-16 P-51PS Ch-16 P-52PS Ch-16 P-53PS Ch-16 P-54PS Ch-16 P-55PS Ch-16 P-56PS Ch-16 P-57PS Ch-16 P-58PS Ch-16 P-59PS Ch-16 P-60PS Ch-16 P-61PS Ch-16 P-62PS Ch-16 P-63PS Ch-16 P-64PS Ch-16 P-65PS Ch-16 P-66PS Ch-16 P-67PS Ch-16 P-68PS Ch-16 P-69PS Ch-16 P-70PS Ch-16 P-71PS Ch-16 P-72PS Ch-16 P-73PS Ch-16 P-74PS Ch-16 P-75PS Ch-16 P-76PS Ch-16 P-77PS Ch-16 P-78PS Ch-16 P-79PS Ch-16 P-80PS Ch-16 P-81PS Ch-16 P-82PS Ch-16 P-83PS Ch-16 P-84PS Ch-16 P-85GQ Ch-16 P-86GQ Ch-16 P-87GQ Ch-16 P-88GQ Ch-16 P-89GQ Ch-16 P-90GQ Ch-16 P-91GQ Ch-16 P-92GQ Ch-16 P-93GQ Ch-16 P-94GQ Ch-16 P-95GQ Ch-16 P-96GQ Ch-16 P-97GQ Ch-16 P-98GQ Ch-16 P-99GQ Ch-16 P-100GQ Ch-16 P-101GQ Ch-16 P-102GQ Ch-16 P-103GQ Ch-16 P-104GQ Ch-16 P-105GQ Ch-16 P-106GQ Ch-16 P-107GQ Ch-16 P-108GQ Ch-16 P-109GQ Ch-16 P-110GQ Ch-16 P-111IL Ch-16 P-112IL Ch-16 P-113IL Ch-16 P-114IL Ch-16 P-115IL Ch-16 P-116IL Ch-16 P-117IL Ch-16 P-118IL Ch-16 P-119SCQ Ch-16 P-120SCQ Ch-16 P-121SCQ Ch-16 P-122SCQ Ch-16 P-123SCQ Ch-16 P-124SCQ Ch-16 P-125SCQ Ch-16 P-126SCQ Ch-16 P-127SCQ Ch-16 P-128SCQ Ch-16 P-129SCQ

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ScienceChemistryChemistry & Chemical Reactivity10th Edition

Chemistry & Chemical Reactivity

Solutions

Chemistry & Chemical Reactivity

What are the equilibrium concentrations of acetic acid, the acetate ion, and H3O+ for a 0.10 M solution of acetic acid (K2 = 1.8 × 10−5)? What is the pH of the solution?

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Chemistry Chemistry & Chemical Reactivity 10th Edition

What are the equilibrium concentrations of acetic acid, the acetate ion, and H₃O⁺ for a 0.10 M solution of acetic acid (K₂ = 1.8 × 10⁻⁵)? What is the pH of the solution?

The is an airway that connects the nose and mouth with the . a. oral cavity; larynx b. pharynx...