Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 16.7, Problem 17P
Treatment of p-bromotoluene with NaOH at 300°C yields a mixture of two products, but treatment of m-bromotoluene with NaOH yields a mixture of three products. Explain.
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Shown below is the 1H NMR spectrum of the alkyl bromide used to make the phosphonium ylide that reacts with a ketone in a Wittig reaction to form a compound with molecular formula C11H14. What product is obtained from the Wittig reaction?
Chapter 16 Solutions
Organic Chemistry
Ch. 16.1 - Prob. 1PCh. 16.2 - Propose a mechanism for the electrophilic...Ch. 16.2 - How many products might be formed on chlorination...Ch. 16.2 - When benzene is treated with D2SŪ4. deuterium...Ch. 16.3 - Prob. 5PCh. 16.3 - What is the major monosubstitution product from...Ch. 16.3 - Identify the carboxylic acid chloride that might...Ch. 16.4 - Rank the compounds in each of the following groups...Ch. 16.4 - Predict the major products of the following...Ch. 16.4 - Prob. 10P
Ch. 16.4 - Prob. 11PCh. 16.4 - Acetanilide is less reactive than aniline toward...Ch. 16.4 - Prob. 13PCh. 16.5 - At what position would you expect electrophilic...Ch. 16.5 - Show the major product(s) from reaction of the...Ch. 16.6 - The herbicide oxyfluorfen can be prepared by...Ch. 16.7 - Treatment of p-bromotoluene with NaOH at 300°C...Ch. 16.8 - Prob. 18PCh. 16.8 - Prob. 19PCh. 16.8 - Prob. 20PCh. 16.9 - Prob. 21PCh. 16.10 - Prob. 22PCh. 16.10 - Prob. 23PCh. 16.SE - Prob. 24VCCh. 16.SE - The following molecular model of a...Ch. 16.SE - Prob. 26VCCh. 16.SE - Prob. 27VCCh. 16.SE - Aromatic iodination can be carried out with a...Ch. 16.SE - Prob. 29MPCh. 16.SE - The carbocation electrophile in a Friede1-Crafts...Ch. 16.SE - Prob. 31MPCh. 16.SE - The nitroso group, —N=O, is one of the few...Ch. 16.SE - Triphenylmethane can be prepared by reaction of...Ch. 16.SE - Using resonance structures of the intermediates,...Ch. 16.SE - Benzene and alkyl -substituted benzenes can be...Ch. 16.SE - Prob. 36MPCh. 16.SE - Hexachlorophene, a substance used in the...Ch. 16.SE - Benzenediazonium carboxylate decomposes when...Ch. 16.SE - 4-Chloropyridine undergoes reaction with...Ch. 16.SE - Propose a mechanism to account for the following...Ch. 16.SE - In the Gatterman-Kochreaction, a formyl group...Ch. 16.SE - Treatment of p-tert-butylphenol with a strong acid...Ch. 16.SE - Benzyl bromide is converted into benzaldehyde by...Ch. 16.SE - Prob. 44MPCh. 16.SE - Prob. 45MPCh. 16.SE - Prob. 46APCh. 16.SE - Prob. 47APCh. 16.SE - Prob. 48APCh. 16.SE - Predict the major monoalkylation products you...Ch. 16.SE - Name and draw the major product(s) of...Ch. 16.SE - Prob. 51APCh. 16.SE - Prob. 52APCh. 16.SE - What product(s) would you expect to obtain from...Ch. 16.SE - Prob. 54APCh. 16.SE - How would you synthesize the following substances...Ch. 16.SE - Prob. 56APCh. 16.SE - Prob. 57APCh. 16.SE - Prob. 58APCh. 16.SE - Prob. 59APCh. 16.SE - Prob. 60APCh. 16.SE - Prob. 61APCh. 16.SE - Prob. 62APCh. 16.SE - Prob. 63APCh. 16.SE - How would you synthesize the following substances...Ch. 16.SE - Prob. 65APCh. 16.SE - Prob. 66APCh. 16.SE - Draw resonance structures of the intermediate...Ch. 16.SE - Prob. 68APCh. 16.SE - p-Bromotoluene reacts with potassium amide to give...Ch. 16.SE - Prob. 70APCh. 16.SE - Prob. 71APCh. 16.SE - Prob. 72APCh. 16.SE - Use your knowledge of directing effects, along...Ch. 16.SE - Identify the reagents represented by the letters...Ch. 16.SE - Phenols (ArOH) are relatively acidic, and the...Ch. 16.SE - Prob. 76APCh. 16.SE - Prob. 77APCh. 16.SE - Melamine, used as a fire retardant and a component...
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- A step in a synthesis of PGE1 (prostaglandin E1, alprostadil) is the reaction of a trisubstituted cyclohexene with bromine to form a bromolactone. Propose a mechanism for formation of this bromolactone and account for the observed stereochemistry of each substituent on the cyclohexane ring. Alprostadil is used as a temporary therapy for infants born with congenital heart defects that restrict pulmonary blood flow. It brings about dilation of the ductus arteriosus, which in turn increases blood flow in the lungs and blood oxygenation.arrow_forwardTreatment of 1-aminoadamantane, C10H17N, with methyl 2,4-dibromobutanoate in the presence of a nonnucleophilic base, R3N, involves two successive SN2 reactions and gives compound A. Propose a structural formula for compound A.arrow_forwardCompound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forward
- Shown below is the 1H NMR spectrum of the alkyl bromide used to make the phosphonium ylide that reacts with a ketone in a Wittig reaction to form acompound with molecular formula C11H14. What product is obtained from the Wittig reaction?arrow_forwardCompound X, C7H14 undergo hydration to form Y which is optically active. X reacts with cold alkane potassium permanganate (VII) solution to form Z. Ozonolysis of X forms methanal and 3,3-dimethylbutanal. Deduce the structure of X,Y and Zarrow_forward19. A compound with molecular formula C6H12O2 exhibits two singlets in its 1H NMR spectrum, at d 1.4 (9H) and d 2.0 (3H). Its IR spectrum shows a strong absorption band near 1740 cm-1. What is the structure for this compound? Show the correlation of the spectra with the molecular structure.arrow_forward
- Undecanal is commercially available, but 6-methyl-1-bromoheptane is not. Propose two methods for the synthesis of 6-methyl-1-bromoheptane using precursors containing fewer than five carbon atoms (Cn n < 5). A protecting group will probably be required.arrow_forwardHydroboration of 2-methyl-2-pentene at 25°C, followed by oxidation with alkaline H2O2, yields 2-methyl-3-pentanol, but hydroboration at 160°C followed by oxidation yields 4- methyl-l-pentanol. Suggest a mechanism.arrow_forwardCompound B of molecular formula C9H19N shows a noteworthy infrared absorption at 3300 cm-1. Its 1H-NMR spectrum shows three singlets – δ 1.0 (6H), 1.1 (12H), 1.4 (1H) ppm. Its 13C-NMR spectrum has four signals – δ 25, 28, 41, 64 ppm. Suggest a structure for this compound. Please show work.arrow_forward
- A compound of formula C6H10O2 shows only two absorptions in the proton NMR: a singlet at 2.67 ppm and a singlet at2.15 ppm. These absorptions have areas in the ratio 2:3. The IR spectrum shows a strong absorption at 1708 cm-1. Proposea structure for this compound.arrow_forwardPropylene oxide is a chiral molecule. Hydrolysis of propylene oxide gives propylene glycol, another chiral molecule. A. Provide a mechanism for the acid-catalyzed hydrolysis of pure (R)-propylene oxide (treatment with H2SO4/H2O), showing the correct stereochemistry. B. Provide a mechanism for the treatment of pure (R)-propylene oxide with NaOH in water (base-catalyzed hydrolysis), showing the correct stereochemistry. C. Explain why acid-catalyzed hydrolysis of optically active propylene oxide gives a product with a rotation in the opposite direction from the product of the base catalyzed hydrolysis.arrow_forwardTreatment of compound A (C8H17Br) with NaOCH2CH3 affords twoconstitutional isomers B and C. Ozonolysis of B affords CH2=O and(CH3CH2CH2)2C=O. Ozonolysis of C affords CH3CH2CH2COCH3 andCH3CH2CHO. What is the structure of A?arrow_forward
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