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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

What is the pH of a 0.10 M solution of oxalic acid, H2C2C4? What are the concentrations of H3O+, HC2O4, and the oxalate ion, C2O42−? (See Appendix H for Ka values.)

Interpretation Introduction

Interpretation:

pH of 0.10 M solution of oxalic acid (H2C2O4) has to be calculated. The concentrations of H3O+, HC2O4- and C2O42- have to be calculated.

Concept introduction:

Dissociation constants are the equilibrium constants for the ionization reactions.

For the general acid HA:

HA (aq) + H2O (l) H3O+ (aq) + A-(aq)                 Ka = [H3O+][A-][HA]

For the general base,

B (aq) + H2O (l) BH+(aq) + OH-(aq)               Kb[BH+][OH-][B]

Explanation

From the given,

Concentration of oxalic acid = 0.10 M.

Oxalic acid is a diprotic acid.

The equilibrium reaction is as follows.

H2C2O4(aq) + H2O(l) H3O+(aq) + HC2O4-(aq)

The constant for the reaction is as follows.

Ka1 =  [H+][HC2O4-][H2C2O4]

The change that occurs as the reaction proceeds to equilibrium and the concentrations hen equilibrium has been established.

H2C2O4(aq)  +H2O(l) H3O+(aq) + HC2O4-(aq)I0.10                     0               0   C-x               x      xE(0.10-x)              x      x

Substitute the all values form the ICE table.

5.9×10-2 = (x)(x)[H2C2O4]5.9×10-2 = (x)2(0.10x)x=0.05278=5.28×102M=5.3×102M

Therefore, concentration of [H3O+] after the first ionization is 5.3×102M.

[H3O+]=[HC2O4]=5.3×102M

Let’s calculate the pH of the solution:

pH= -log[H3O+]= -log(5.3×102M)= 1

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Sect-16.10 P-1.2ACPSect-16.10 P-1.3ACPSect-16.10 P-2.1ACPSect-16.10 P-2.2ACPSect-16.10 P-2.3ACPSect-16.10 P-2.4ACPSect-16.10 P-2.5ACPCh-16 P-1PSCh-16 P-2PSCh-16 P-3PSCh-16 P-4PSCh-16 P-5PSCh-16 P-6PSCh-16 P-7PSCh-16 P-8PSCh-16 P-9PSCh-16 P-10PSCh-16 P-11PSCh-16 P-12PSCh-16 P-13PSCh-16 P-14PSCh-16 P-15PSCh-16 P-16PSCh-16 P-17PSCh-16 P-18PSCh-16 P-19PSCh-16 P-20PSCh-16 P-21PSCh-16 P-22PSCh-16 P-23PSCh-16 P-24PSCh-16 P-25PSCh-16 P-26PSCh-16 P-27PSCh-16 P-28PSCh-16 P-29PSCh-16 P-30PSCh-16 P-31PSCh-16 P-32PSCh-16 P-33PSCh-16 P-34PSCh-16 P-35PSCh-16 P-36PSCh-16 P-37PSCh-16 P-38PSCh-16 P-39PSCh-16 P-40PSCh-16 P-41PSCh-16 P-42PSCh-16 P-43PSCh-16 P-44PSCh-16 P-45PSCh-16 P-46PSCh-16 P-47PSCh-16 P-48PSCh-16 P-49PSCh-16 P-50PSCh-16 P-51PSCh-16 P-52PSCh-16 P-53PSCh-16 P-54PSCh-16 P-55PSCh-16 P-56PSCh-16 P-57PSCh-16 P-58PSCh-16 P-59PSCh-16 P-60PSCh-16 P-61PSCh-16 P-62PSCh-16 P-63PSCh-16 P-64PSCh-16 P-65PSCh-16 P-66PSCh-16 P-67PSCh-16 P-68PSCh-16 P-69PSCh-16 P-70PSCh-16 P-71PSCh-16 P-72PSCh-16 P-73PSCh-16 P-74PSCh-16 P-75PSCh-16 P-76PSCh-16 P-77PSCh-16 P-78PSCh-16 P-79PSCh-16 P-80PSCh-16 P-81PSCh-16 P-82PSCh-16 P-83PSCh-16 P-84PSCh-16 P-85GQCh-16 P-86GQCh-16 P-87GQCh-16 P-88GQCh-16 P-89GQCh-16 P-90GQCh-16 P-91GQCh-16 P-92GQCh-16 P-93GQCh-16 P-94GQCh-16 P-95GQCh-16 P-96GQCh-16 P-97GQCh-16 P-98GQCh-16 P-99GQCh-16 P-100GQCh-16 P-101GQCh-16 P-102GQCh-16 P-103GQCh-16 P-104GQCh-16 P-105GQCh-16 P-106GQCh-16 P-107GQCh-16 P-108GQCh-16 P-109GQCh-16 P-110GQCh-16 P-111ILCh-16 P-112ILCh-16 P-113ILCh-16 P-114ILCh-16 P-115ILCh-16 P-116ILCh-16 P-117ILCh-16 P-118ILCh-16 P-119SCQCh-16 P-120SCQCh-16 P-121SCQCh-16 P-122SCQCh-16 P-123SCQCh-16 P-124SCQCh-16 P-125SCQCh-16 P-126SCQCh-16 P-127SCQCh-16 P-128SCQCh-16 P-129SCQ

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