   Chapter 17, Problem 112AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# . Approximately 0.14 g of nickel(II) hydroxide. Ni ( OH ) 2 ( s ) , dissolves per liter of water at 20 °C. Calculate Kspfor Ni ( OH ) 2 ( s ) at this temperature.

Interpretation Introduction

Interpretation:

The Ksp value for Ni(OH)2(s) at 20°C is to be calculated.

Concept Introduction:

The equilibrium expression is used to calculate the solubility and solubility product constant of salts. The equilibrium expression for Ni(OH)2(s) is,

Ksp=[Ni2+][OH]2.

Explanation

The given solubility of Ni(OH)2(s) is 0.14gL1.

The molar mass of Ni(OH)2(s) is =1×Ni+2×O+2×H=1×58.69gmol1+2×16gmol1+2×1gmol1=92.69gmol1

The conversion of solubility of Ni(OH)2(s) in molL1 is,

=0.14gNi(OH)2L×1molNi(OH)292.69gNi(OH)2=1.51×103molL1

It is assumed that 1.51×103molL1 of Ni(OH)2(s), is dissolved to reach the equilibrium stage. Thus,

1.51×103molLNi(OH)2(s)1.51×103molLNi2+(aq)+2(1.51×103)molLOH(aq)

At equilibrium,

[Ni2+]=1

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