Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Question
Chapter 17, Problem 17.85AP
Interpretation Introduction

Interpretation: The ratio of [Ag+] to [Ag(S2O3)23] in a bath in which [(S2O3)23] is equal to 0.250M is to be calculated.

Concept introduction: The relation between equilibrium constant and concentration of reactants and product is given as,

Kf=[Ag(S2O3)23][Ag+]+[S2O32]

To determine: The ratio of [Ag+] to [Ag(S2O3)23] in a bath in which [(S2O3)23].

Expert Solution & Answer
Check Mark

Answer to Problem 17.85AP

The ratio of [Ag+] to [Ag(S2O3)23] in a bath in which [(S2O3)23] equal to 0.250M is 3.20×10-13_.

Explanation of Solution

Given

The concentration of S2O32 is 0.250M.

The value of Kf is 5×1013.

The given reaction is,

Ag+(aq)+2S2O32(aq)[Ag(S2O3)23](aq)Kf=5×1013

The expression for Kf value is given as,

Kf=[Ag(S2O3)23][Ag+]+[S2O32] (1)

Where,

  • [Ag(S2O3)23] is the concentration of sodium thiosulphate.
  • [Ag+] is the concentration of silver cation
  • [S2O32] is the concentration of anion.
  • Kf is the equilibrium constant.

Substitute the values of [Ag(S2O3)23],[Ag+]and[S2O32] in the equation (1).

Chemistry, Chapter 17, Problem 17.85AP 5×1013=[Ag(S2O3)23][Ag+]+[0.250]25×1013=[Ag(S2O3)23][Ag+]+(0.0625)[Ag(S2O3)23][Ag+]=5×1013(0.0625)[Ag(S2O3)23][Ag+]=3.12×1012

Simplify the above expression,

[Ag+][Ag(S2O3)23]=13.12×1012=3.20×10-13_

Therefore, the ratio of [Ag+] to [Ag(S2O3)23] in a bath in which [(S2O3)23] equal to 0.250M is 3.20×10-13_.

Conclusion

The ratio of [Ag+] to [Ag(S2O3)23] in a bath in which [(S2O3)23] equal to 0.250M is 3.20×10-13_.

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Chapter 17 Solutions

Chemistry

Ch. 17 - Prob. 17.5VPCh. 17 - Prob. 17.6VPCh. 17 - Prob. 17.7VPCh. 17 - Prob. 17.8VPCh. 17 - Prob. 17.9VPCh. 17 - Prob. 17.10VPCh. 17 - Prob. 17.11QPCh. 17 - Prob. 17.12QPCh. 17 - Prob. 17.13QPCh. 17 - Prob. 17.14QPCh. 17 - Prob. 17.15QPCh. 17 - Prob. 17.16QPCh. 17 - Prob. 17.17QPCh. 17 - Prob. 17.18QPCh. 17 - Prob. 17.19QPCh. 17 - Prob. 17.20QPCh. 17 - Prob. 17.21QPCh. 17 - Prob. 17.22QPCh. 17 - Prob. 17.23QPCh. 17 - Prob. 17.24QPCh. 17 - Prob. 17.25QPCh. 17 - Prob. 17.26QPCh. 17 - Prob. 17.28QPCh. 17 - Prob. 17.29QPCh. 17 - Prob. 17.30QPCh. 17 - Prob. 17.31QPCh. 17 - Prob. 17.32QPCh. 17 - Prob. 17.33QPCh. 17 - Prob. 17.34QPCh. 17 - Prob. 17.35QPCh. 17 - Prob. 17.36QPCh. 17 - Prob. 17.37QPCh. 17 - Prob. 17.38QPCh. 17 - Prob. 17.39QPCh. 17 - Prob. 17.40QPCh. 17 - Prob. 17.41QPCh. 17 - Prob. 17.42QPCh. 17 - Prob. 17.43QPCh. 17 - Prob. 17.44QPCh. 17 - Prob. 17.45QPCh. 17 - Prob. 17.46QPCh. 17 - Prob. 17.47QPCh. 17 - Prob. 17.48QPCh. 17 - Prob. 17.49QPCh. 17 - Prob. 17.50QPCh. 17 - Prob. 17.51QPCh. 17 - Prob. 17.52QPCh. 17 - Prob. 17.53QPCh. 17 - Prob. 17.54QPCh. 17 - Prob. 17.55QPCh. 17 - Prob. 17.56QPCh. 17 - Prob. 17.57QPCh. 17 - Prob. 17.58QPCh. 17 - Prob. 17.59QPCh. 17 - Prob. 17.60QPCh. 17 - Prob. 17.61QPCh. 17 - Prob. 17.62QPCh. 17 - Prob. 17.63QPCh. 17 - Prob. 17.64QPCh. 17 - Prob. 17.65QPCh. 17 - Prob. 17.66QPCh. 17 - Prob. 17.67QPCh. 17 - Prob. 17.68QPCh. 17 - Prob. 17.69QPCh. 17 - Prob. 17.70QPCh. 17 - Prob. 17.71QPCh. 17 - Prob. 17.72QPCh. 17 - Prob. 17.73QPCh. 17 - Prob. 17.74QPCh. 17 - Prob. 17.75QPCh. 17 - Prob. 17.76QPCh. 17 - Prob. 17.77QPCh. 17 - Prob. 17.78QPCh. 17 - Prob. 17.79QPCh. 17 - Prob. 17.80QPCh. 17 - Prob. 17.81QPCh. 17 - Prob. 17.82QPCh. 17 - Prob. 17.83QPCh. 17 - Prob. 17.84QPCh. 17 - Prob. 17.85APCh. 17 - Prob. 17.86APCh. 17 - Prob. 17.87APCh. 17 - Prob. 17.88APCh. 17 - Prob. 17.89APCh. 17 - Prob. 17.90APCh. 17 - Prob. 17.91AP
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