   Chapter 17, Problem 17.10P Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939

Solutions

Chapter
Section Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939
Textbook Problem

Refer to the footing in Problem 17.8. For calculating elastic settlement under the footing, it is necessary to estimate the elastic modulus of the foundation soil. Using qc from Problem 17.9 and Eq. (17.33), estimate the variation of elastic modulus with depth for the soil profile shown in Figure 17.16. Figure 17.16Refer to Problem 17.7 and Figure 17.16. Suppose a footing (1.5 m × 1.5 m) is constructed at a depth of 1 m.a. Estimate the design values for N60 and ϕ ′ .b. What is the net allowable load that the footing can carry? The maximum allowable settlement is 25 mm. Use Eqs. (16.56) and (16.61).

To determine

Find the modulus elasticity of the foundation soil with the various depth.

Explanation

Given information:

The atmospheric pressure is (pa) 100kN/m2.

Assume the grain size (D50) 0.46mm.

Show the depth and number of blows shown in table:

 Depth,(m) N60 1 6 2.5 8 4 11 5.5 13 7 14 8.5 16

Calculation:

Show the expression of correlation between qcandN60 using the Equation:

(qcpa)N60=cD50a (1)

Here, pa is atmospheric pressure, N60 is standard penetration resistance, c and a as developed from various studies.

For c and a value given by Kulhawy and Mayne(1990).

Refer Table 17.7 in section 17.11 “Cone penetration test” in the textbook.

 c a 5.44 0.26

Find the variation of cone penetration resistance with various depth 1m

Substitute 100kN/m2 for pa, 0.46mm for D50, 5.44 for c, 0.26 for a, and 6 for N60 in Equation (1).

(qc100)6=5.44(0.46)0.26(qc100)6=4.4454(qc100)=26.67qc=2,667kN/m2

Find the variation of cone penetration resistance with various depth 2.5m.

Substitute 100kN/m2 for pa, 0.46mm for D50, 5.44 for c, 0.26 for a, and 8 for N60 in Equation (1).

(qc100)6=5.44(0.46)0.26(qc100)8=4.4454(qc100)=35.56qc=3,556kN/m2

Find the variation of cone penetration resistance with various depth 4m.

Substitute 100kN/m2 for pa, 0.46mm for D50, 5.44 for c, 0.26 for a, and 11 for N60 in Equation (1).

(qc100)6=5.44(0.46)0.26(qc100)11=4.4454(qc100)=48.89qc=4,890kN/m2

Find the variation of cone penetration resistance with various depth 5.5m.

Substitute 100kN/m2 for pa, 0.46mm for D50, 5.44 for c, 0.26 for a, and 13 for N60 in Equation (1).

(qc100)6=5.44(0.46)0.26(qc100)13=4.4454(qc100)=57.79qc=5,779kN/m2

Find the variation of cone penetration resistance with various depth 7m.

Substitute 100kN/m2 for pa, 0.46mm for D50, 5.44 for c, 0.26 for a, and 14 for N60 in Equation (1).

(qc100)6=5.44(0.46)0.26(qc100)14=4

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