General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN: 9781285853918
Author: H. Stephen Stoker
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 17, Problem 17.131EP

(a)

Interpretation Introduction

Interpretation:

The organic product formed in the given reaction has to be indicated as primary amide, secondary amide, tertiary amide, or not an amide.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(a)

Expert Solution
Check Mark

Answer to Problem 17.131EP

Organic product obtained is a primary amide.

Explanation of Solution

Given reaction is,

General, Organic, and Biological Chemistry, Chapter 17, Problem 17.131EP , additional homework tip  1

In amidification process, OH from carboxylic acid and H from amine or ammonia is lost to form amide as product.  Looking into the given reaction, it is found that a carboxylic acid and ammonia is present as reactant and the reaction is conducted at high temperature.  The product obtained is a primary amide.  This is an amidification reaction.

General, Organic, and Biological Chemistry, Chapter 17, Problem 17.131EP , additional homework tip  2

Conclusion

The product obtained is indicated.

(b)

Interpretation Introduction

Interpretation:

The organic product formed in the given reaction has to be indicated as primary amide, secondary amide, tertiary amide, or not an amide.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(b)

Expert Solution
Check Mark

Answer to Problem 17.131EP

Organic product obtained is a secondary amide.

Explanation of Solution

Given reaction is,

General, Organic, and Biological Chemistry, Chapter 17, Problem 17.131EP , additional homework tip  3

In amidification process, OH from carboxylic acid and H from amine or ammonia is lost to form amide as product.  Looking into the given reaction, it is found that a carboxylic acid and primary amine is present as reactant and the reaction is conducted at high temperature.  The product obtained is a secondary amide.  This is an amidification reaction.

General, Organic, and Biological Chemistry, Chapter 17, Problem 17.131EP , additional homework tip  4

Conclusion

The product obtained is indicated.

(c)

Interpretation Introduction

Interpretation:

The organic product formed in the given reaction has to be indicated as primary amide, secondary amide, tertiary amide, or not an amide.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(c)

Expert Solution
Check Mark

Answer to Problem 17.131EP

Organic product obtained is a tertiary amide.

Explanation of Solution

Given reaction is,

General, Organic, and Biological Chemistry, Chapter 17, Problem 17.131EP , additional homework tip  5

In amidification process, OH from carboxylic acid and H from amine or ammonia is lost to form amide as product.  Looking into the given reaction, it is found that a carboxylic acid and secondary amine is present as reactant and the reaction is conducted at high temperature.  The product obtained is a tertiary amide.  This is an amidification reaction.

General, Organic, and Biological Chemistry, Chapter 17, Problem 17.131EP , additional homework tip  6

Conclusion

The product obtained is indicated.

(d)

Interpretation Introduction

Interpretation:

The organic product formed in the given reaction has to be indicated as primary amide, secondary amide, tertiary amide, or not an amide.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(d)

Expert Solution
Check Mark

Answer to Problem 17.131EP

Organic product obtained is a tertiary amide.

Explanation of Solution

Given reaction is,

General, Organic, and Biological Chemistry, Chapter 17, Problem 17.131EP , additional homework tip  7

In amidification process, OH from carboxylic acid and H from amine or ammonia is lost to form amide as product.  Looking into the given reaction, it is found that a carboxylic acid and secondary amine is present as reactant and the reaction is conducted at high temperature.  The product obtained is a tertiary amide.  This is an amidification reaction.

General, Organic, and Biological Chemistry, Chapter 17, Problem 17.131EP , additional homework tip  8

Conclusion

The product obtained is indicated.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 17 Solutions

General, Organic, and Biological Chemistry

Ch. 17.4 - Prob. 1QQCh. 17.4 - Prob. 2QQCh. 17.5 - Prob. 1QQCh. 17.5 - Prob. 2QQCh. 17.5 - Prob. 3QQCh. 17.6 - Prob. 1QQCh. 17.6 - Prob. 2QQCh. 17.6 - Prob. 3QQCh. 17.7 - Prob. 1QQCh. 17.7 - Prob. 2QQCh. 17.7 - Prob. 3QQCh. 17.8 - Prob. 1QQCh. 17.8 - Prob. 2QQCh. 17.8 - Prob. 3QQCh. 17.8 - Prob. 4QQCh. 17.9 - Prob. 1QQCh. 17.9 - Prob. 2QQCh. 17.10 - Prob. 1QQCh. 17.10 - Prob. 2QQCh. 17.10 - Prob. 3QQCh. 17.10 - Prob. 4QQCh. 17.11 - Prob. 1QQCh. 17.11 - Prob. 2QQCh. 17.11 - Prob. 3QQCh. 17.12 - Prob. 1QQCh. 17.12 - Prob. 2QQCh. 17.12 - Prob. 3QQCh. 17.12 - Prob. 4QQCh. 17.13 - Prob. 1QQCh. 17.13 - Prob. 2QQCh. 17.13 - Prob. 3QQCh. 17.13 - Prob. 4QQCh. 17.14 - Prob. 1QQCh. 17.14 - Prob. 2QQCh. 17.14 - Prob. 3QQCh. 17.15 - Prob. 1QQCh. 17.15 - Prob. 2QQCh. 17.16 - Prob. 1QQCh. 17.16 - Prob. 2QQCh. 17.16 - Prob. 3QQCh. 17.17 - Prob. 1QQCh. 17.17 - Prob. 2QQCh. 17.17 - Prob. 3QQCh. 17.18 - Prob. 1QQCh. 17.18 - Prob. 2QQCh. 17.18 - Prob. 3QQCh. 17.19 - Prob. 1QQCh. 17.19 - Prob. 2QQCh. 17.19 - Prob. 3QQCh. 17.19 - Prob. 4QQCh. 17 - Prob. 17.1EPCh. 17 - Prob. 17.2EPCh. 17 - Prob. 17.3EPCh. 17 - Prob. 17.4EPCh. 17 - Prob. 17.5EPCh. 17 - Prob. 17.6EPCh. 17 - Indicate whether or not each of the following...Ch. 17 - Indicate whether or not each of the following...Ch. 17 - Prob. 17.9EPCh. 17 - Prob. 17.10EPCh. 17 - Prob. 17.11EPCh. 17 - Prob. 17.12EPCh. 17 - Prob. 17.13EPCh. 17 - Prob. 17.14EPCh. 17 - Prob. 17.15EPCh. 17 - Assign a common name to each of the following...Ch. 17 - Prob. 17.17EPCh. 17 - Prob. 17.18EPCh. 17 - Prob. 17.19EPCh. 17 - Prob. 17.20EPCh. 17 - Prob. 17.21EPCh. 17 - Prob. 17.22EPCh. 17 - Prob. 17.23EPCh. 17 - Prob. 17.24EPCh. 17 - Prob. 17.25EPCh. 17 - Prob. 17.26EPCh. 17 - Prob. 17.27EPCh. 17 - Prob. 17.28EPCh. 17 - Prob. 17.29EPCh. 17 - Prob. 17.30EPCh. 17 - Prob. 17.31EPCh. 17 - Prob. 17.32EPCh. 17 - Prob. 17.33EPCh. 17 - Prob. 17.34EPCh. 17 - Determine the maximum number of hydrogen bonds...Ch. 17 - Prob. 17.36EPCh. 17 - Prob. 17.37EPCh. 17 - Prob. 17.38EPCh. 17 - Prob. 17.39EPCh. 17 - Prob. 17.40EPCh. 17 - Prob. 17.41EPCh. 17 - Prob. 17.42EPCh. 17 - Prob. 17.43EPCh. 17 - Prob. 17.44EPCh. 17 - Prob. 17.45EPCh. 17 - Prob. 17.46EPCh. 17 - Prob. 17.47EPCh. 17 - Prob. 17.48EPCh. 17 - Prob. 17.49EPCh. 17 - Prob. 17.50EPCh. 17 - Prob. 17.51EPCh. 17 - Prob. 17.52EPCh. 17 - Prob. 17.53EPCh. 17 - Prob. 17.54EPCh. 17 - Prob. 17.55EPCh. 17 - Prob. 17.56EPCh. 17 - Prob. 17.57EPCh. 17 - Prob. 17.58EPCh. 17 - Prob. 17.59EPCh. 17 - Prob. 17.60EPCh. 17 - Prob. 17.61EPCh. 17 - Prob. 17.62EPCh. 17 - Prob. 17.63EPCh. 17 - Prob. 17.64EPCh. 17 - Prob. 17.65EPCh. 17 - Prob. 17.66EPCh. 17 - Prob. 17.67EPCh. 17 - Prob. 17.68EPCh. 17 - Prob. 17.69EPCh. 17 - Prob. 17.70EPCh. 17 - Prob. 17.71EPCh. 17 - Prob. 17.72EPCh. 17 - Prob. 17.73EPCh. 17 - Prob. 17.74EPCh. 17 - Prob. 17.75EPCh. 17 - Prob. 17.76EPCh. 17 - Prob. 17.77EPCh. 17 - Prob. 17.78EPCh. 17 - Prob. 17.79EPCh. 17 - Prob. 17.80EPCh. 17 - Prob. 17.81EPCh. 17 - Prob. 17.82EPCh. 17 - Prob. 17.83EPCh. 17 - Prob. 17.84EPCh. 17 - Prob. 17.85EPCh. 17 - Prob. 17.86EPCh. 17 - Prob. 17.87EPCh. 17 - Prob. 17.88EPCh. 17 - Prob. 17.89EPCh. 17 - Prob. 17.90EPCh. 17 - Prob. 17.91EPCh. 17 - Prob. 17.92EPCh. 17 - Prob. 17.93EPCh. 17 - Prob. 17.94EPCh. 17 - Prob. 17.95EPCh. 17 - Prob. 17.96EPCh. 17 - Prob. 17.97EPCh. 17 - Prob. 17.98EPCh. 17 - Indicate whether or not each of the following...Ch. 17 - Indicate whether or not each of the following...Ch. 17 - Classify each of the following amides as...Ch. 17 - Classify each of the following amides as...Ch. 17 - Classify each of the amides in Problem 17-101 as a...Ch. 17 - Prob. 17.104EPCh. 17 - Prob. 17.105EPCh. 17 - Prob. 17.106EPCh. 17 - Prob. 17.107EPCh. 17 - Prob. 17.108EPCh. 17 - Prob. 17.109EPCh. 17 - Prob. 17.110EPCh. 17 - Assign an IUPAC name to each of the following...Ch. 17 - Assign an IUPAC name to each of the following...Ch. 17 - Prob. 17.113EPCh. 17 - Prob. 17.114EPCh. 17 - Prob. 17.115EPCh. 17 - Prob. 17.116EPCh. 17 - Prob. 17.117EPCh. 17 - Prob. 17.118EPCh. 17 - Prob. 17.119EPCh. 17 - What is the relationship between the acronym DEET...Ch. 17 - Prob. 17.121EPCh. 17 - Prob. 17.122EPCh. 17 - Prob. 17.123EPCh. 17 - Prob. 17.124EPCh. 17 - Prob. 17.125EPCh. 17 - Prob. 17.126EPCh. 17 - Prob. 17.127EPCh. 17 - Prob. 17.128EPCh. 17 - Prob. 17.129EPCh. 17 - Prob. 17.130EPCh. 17 - Prob. 17.131EPCh. 17 - Prob. 17.132EPCh. 17 - Prob. 17.133EPCh. 17 - Prob. 17.134EPCh. 17 - Prob. 17.135EPCh. 17 - Prob. 17.136EPCh. 17 - Prob. 17.137EPCh. 17 - Prob. 17.138EPCh. 17 - Prob. 17.139EPCh. 17 - Prob. 17.140EPCh. 17 - Prob. 17.141EPCh. 17 - Prob. 17.142EPCh. 17 - Prob. 17.143EPCh. 17 - Prob. 17.144EPCh. 17 - Prob. 17.145EPCh. 17 - Prob. 17.146EPCh. 17 - Prob. 17.147EPCh. 17 - Prob. 17.148EPCh. 17 - Prob. 17.149EPCh. 17 - Prob. 17.150EPCh. 17 - Prob. 17.151EPCh. 17 - Prob. 17.152EPCh. 17 - Prob. 17.153EPCh. 17 - Prob. 17.154EP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Organic And Biological Chemistry
Chemistry
ISBN:9781305081079
Author:STOKER, H. Stephen (howard Stephen)
Publisher:Cengage Learning,
Text book image
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Nomenclature: Crash Course Chemistry #44; Author: CrashCourse;https://www.youtube.com/watch?v=U7wavimfNFE;License: Standard YouTube License, CC-BY