Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 17, Problem 17.21E
Interpretation Introduction

(a)

Interpretation:

The classification of the given monosaccharide as an aldo-or keto- triose, tetrose, pentose, or hexose is to be stated.

Concept introduction:

Carbohydrates are the polyhydroxy aldehydes or ketones or in other words, the substances that give polyhydroxy aldehydes or ketones are called carbohydrates. They can be classified on the basis of number of carbon atoms and referred as triose, tetrose, pentose and hexose when it contains three, four, five and six carbon atoms respectively. Monosaccharide is the polyhydroxy aldehyde or ketone that contains only one aldehyde or ketone unit. Monosaccharide does not undergo hydrolysis.

Interpretation Introduction

(b)

Interpretation:

The classification of the given monosaccharide as an aldo- or keto- triose, tetrose, pentose, or hexose is to be stated.

Concept introduction:

Carbohydrates are the polyhydroxy aldehydes or ketones or in other words the substances that give polyhydroxy aldehydes or ketones are called carbohydrates. They can be classified on the basis of number of carbon atoms and referred as triose, tetrose, pentose and hexose when it contains three, four, five and six carbon atoms respectively. Monosaccharide is the polyhydroxy aldehyde or ketone that contains only one aldehyde or ketone unit. Monosaccharide does not undergo hydrolysis.

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Chapter 17 Solutions

Chemistry for Today: General, Organic, and Biochemistry

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