   Chapter 17, Problem 19Q

Chapter
Section
Textbook Problem

# The third law of thermodynamics states that the entropy of a perfect crystal at 0 K is zero. In Appendix 4, F−(aq), OH−(aq), and S2−(aq) all have negative standard entropy values. How can S° values be less than zero?

Interpretation Introduction

Interpretation: An explanation corresponding to some of the ionic species having the S° values less than zero is to be stated.

Concept introduction: Entropy is defined as the degree of randomness in a given system. According to the third law of thermodynamics, the entropy of a perfect crystal is zero at 0K .

Explanation

Explanation

According to the third law of thermodynamics, the entropy of a perfect crystal is zero at 0K . It is applicable to perfectly crystalline solids. This does not hold true for the aqueous species.

The given substances, F , OH

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Find more solutions based on key concepts 