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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

Starting from Ohm’s law, show that E = , where E is the magnitude of the electric field (assumed constant) and J = I/A is called the current density. The result is in fact true in general.

To determine
The proof shows that the equation E=Jρ is the equivalent form of ohms law.

Explanation

Given Info: Another form of ohms law is given by E=Jρ . E is the magnitude of electric current. J is the current density J=IA .

Explanation:

Formula to calculate the magnitude of electric field is given by

E=ΔVL

  • E is the magnitude of electric field
  • ΔV is the applied voltage across the conductor,
  • L is the length of the conductor,

Ohms law is given by

ΔV=IR

  • I is the current passing through the conductor,
  • R is the resistance of conductor,

Use IR for ΔV in E=ΔVL to rewrite E

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